How do you solve 7.2>0.9(n+8.6)

1 answer:

6 0

7.2>0.9(n+8.6)
multiply 0.9 by all in parentheses

7.2> (0.9*n) + (0.9*8.6)
7.2> 0.9n + 7.74

subtract 7.74 from both sides
-0.54> 0.9n

divide both sides by 0.9
-0.6> n

ANSWER: -0.6> n

Hope this helps! :)

You might be interested in

The length of Joseph’s rectangular poster is two times it’s width. If the perimeter is 24 inches, what is the area of the poster

leonid [27]

Let's assign the width to a variable, with that variable being x. the length is two times the width, so it would be 2x. the perimeter of a rectangle is length + length + width + width, so you would add 2x + 2x + x + x = 24 inches. combine like terms (x) to get 6x = 24. divide both sides by 6 to get x = 4. so the width (x) is 4, and the length (2x) is 8. the area of a rectangle is length times width, so multiply 4 * 8. that would get you 32 inches^2.

6 0

4 years ago

Find the value of this expression if x = -4.<br> x2 – 7<br> x + 1

Eduardwww [97]

Answer:

First one equals -15

Second one equals -3

Step-by-step explanation:

(-4)*2 - 7

= (-8) - 7

= (-15)

(-4) + 1

= (-3)

Hopefully this helps.

3 0

3 years ago

Let $DEF$ be an equilateral triangle with side length $3.$ At random, a point $G$ is chosen inside the triangle. Compute the pro

umka21 [38]

$|\Omega|=(\text{the area of the triangle})=\dfrac{a^2\sqrt3}{4}=\dfrac{3^2\sqrt3}{4}=\dfrac{9\sqrt3}{4}\\|A|=(\text{the area of the sector})=\dfrac{\alpha\pi r^2}{360}=\dfrac{60\pi \cdot 1^2}{360}=\dfrac{\pi}{6}\\\\\\P(A)=\dfrac{\dfrac{\pi}{6}}{\dfrac{9\sqrt3}{4}}\\\\P(A)=\dfrac{\pi}{6}\cdot\dfrac{4}{9\sqrt3}\\\\P(A)=\dfrac{2\pi}{27\sqrt3}\\\\P(A)=\dfrac{2\pi\sqrt3}{27\cdot3}\\\\P(A)=\dfrac{2\pi\sqrt3}{81}\approx13.4\%$