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Alla [95]
3 years ago
9

Jack picked a card from a standard deck. What is the probability that jack picked a diamond or a queen?

Mathematics
2 answers:
Vika [28.1K]3 years ago
8 0
Picking a diamond is 1/4, and picking a queen is a 1/13 chance
andrey2020 [161]3 years ago
4 0

Answer:

probability is 4 / 13

Step-by-step explanation:

Total number of cards in a standard deck = 52 cards.

total number of diamonds = 13 cards

total number of queens = 4 cards.

We should remember that in 13 cards of diamonds there is one queen. so total diamonds and queens are = 13 + 3 = 16 cards

The probability that Jack picked a diamond or a queen

= 16 / 52 = 4 / 13

You might be interested in
Given the arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103,...
omeli [17]

We are given

arithmetic sequence: u(1)= 124, u(2)= 117, u(3)= 110, u(4)=103

so, first term is 124

u(1)= 124

now, we can find common difference

d=u(2)-u(1)

d=117-124

d=-7

now, we can find kth term

u(k)=u(1)+(k-1)d

now, we can plug values

and we get

u(k)=124+(k-1)*-7

u(k)=124-7k+7

u(k)=131-7k

u(k) must be negative

so,

u(k)=131-7k

131-7k

now, we can solve for k

7k>131

k>18.714

so, it's closest integer value is

k=19..............Answer


3 0
3 years ago
How would you estimate 412÷97?
marissa [1.9K]
Your answer would be 4.23 as the answer will be a long one, estimated.
6 0
3 years ago
10 + 2-x\3 = 7<br><br><br> \ = divided by<br><br> TIA!
Lemur [1.5K]
Your answer to this problem is 15


10 + 2 - 15 / 3 = 7


Hope it helped :)

8 0
3 years ago
.<br><br> y = x2 + 3<br> y = x + 5
ddd [48]
I assume you mean x squared in the first equation

Because both are equal to y, they are equal to each other so x + 5 = x^2 +3
If we then move everything over to one side, we get x^2 - x - 2 = 0

Then factorise it to (x-2)(x+1) = 0
And solve both parts separately

x + 1 = 0
x = -1

x-2 = 0
x = 2

Sub both values into the simplest equation in this case y=x+5
to get y = 4 and y = 7
7 0
1 year ago
A scientist mixes water (containing no salt) with a solution that contains 35% salt. She wants to obtain 105 ounces of a mixture
Naya [18.7K]

Answer:

60 oz of water to add

45 oz of 35% salt solution should be used

Step-by-step explanation:

Let x = amt no. ounces in the first solution

and  105 - x = amt no. of ounces in the second solution

Ist solution contains 0% salt

2nd solution contains .35(105 - x) salt

.15(105= amt of salt in mix

So.

amt of salt in 1st solution + amt of salt in 2nd solution = amt of salt in the mix

0 + .35(105 - x) = .15(105)

Let's get rid of the fractions by multipying thru the equation by 100

35(105 - x) = 15(105)

3675 - 35x = 1575

-35x = -2100

x = 60 oz of water to add

105 - 60 = 45 oz of 35% salt solution should be used

7 0
2 years ago
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