Answer:
Imagine Dragon
Explanation:
These balls across yo face
Gottem
A) solid
B) liquid
C) gas
D) Shows the temperature and pressure conditions under which a solid water and water vapor can co exist
E) liquid
Answer:it’s called osmosis
Explanation:Osmosis is a specific type of diffusion; it is the passage of water from a region of high water concentration through a semi-permeable membrane to a region of low water concentration.
The solubility of a substance in water is dependent on the temperature. Thus for
1 & 2: Temperature is the independent variable (the one that changes in the first place) and Solubility is a dependent variable (a variable that changes in response to changes in the independent variable.)
The graph: by convention you shall label the horizontal axis with the independent variable and the vertical axis with the dependent variable. For clarity's sake you shall use the finest scale possible that accommodates for all data provided for both axis. Plot the data points on the graph as if they are points on a cartesian plane.
My teacher made no detailed requirements on the phrasing on titles of solubility curve plots; however, like most other graphs in chemistry, the title shall specify the name of variables presented in this visualization. For instance, "the solubility of
under different temperatures" might do. You shall refer to your textbooks for such convention.
It is necessary to interpolate to find the solubility at a temperature not given in the table. Start by connecting all given data points with a smooth line; find the vertical line corresponding to temperature = 75 degree Celsius and determine the solubility at the intersection of the vertical line and the trend line. That point shall approximates the solubility of the salt at that temperature.
Answer:
There are 2.258 x 10^24 molecules of CO2 in 165 grams of CO2.
Explanation:
First you have to calculate the molar mass of carbon dioxide ⇒ 44 grs/mol. Then,
44 grs ------------- 1 mol CO2
165 grs ------------ x = 3.75 moles of CO2.
Then, from Avogadros constant we have that there are 6.022 x 10^23 molecules in 1 mol. So,
1 mol CO2 ---------------- 6.022 x 10^23 molecules CO2
3.75 moles CO2-------- x = 2.258 x 10^24 molecules CO2.
There are 2.258 x 10^24 molecules CO2 in 165 grams of CO2.