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Gemiola [76]
3 years ago
12

Pure gold is defined as having 24 carats. When mixed in an alloy, the carats of gold are given as a percentage of this value. Fo

r example, a piece of jewelry made with 50% gold has 12 carats. State the purity of this piece of red gold jewelry in carats.
Chemistry
1 answer:
kap26 [50]3 years ago
4 0

Answer:

18 Carats because of 75% Purity...

Explanation:

Red Gold Jewelry always contains a mixing of 25% copper by mass to make it durable and strong. That according to the simple parallel ratio rule, gives us a purity level of gold to be exactly 18 Carats. In other words the Red Gold is 75% pure...

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How many water molecules self ionize in one liter of water
Drupady [299]

Answer:

yes

Explanation:

because I think it is correct fo u

5 0
3 years ago
Iron is biologically important in the transport of oxygen by red blood cells from the lungs to the various organs of the body. I
Aneli [31]

Answer : The number of iron atoms present in each red blood cell are, 1.077\times 10^9

Explanation :

First we have to calculate the moles of iron.

\text{Moles of iron}=\frac{\text{Mass of iron}}{\text{Molar mass of iron}}=\frac{2.90g}{55.85g/mole}=0.0519moles

Now we have to calculate the number of iron atoms.

As, 1 mole of iron contains 6.022\times 10^{23} number of iron atoms

So, 0.0519 mole of iron contains 0.0519\times 6.022\times 10^{23}=3.125\times 10^{22} number of iron atoms

Now we have to calculate the number of iron atoms are present in each red blood cell.

Number of iron atoms are present in each red blood cell = \frac{\text{Number of iron atoms}}{\text{Total number of red blood cells}}

Number of iron atoms are present in each red blood cell = \frac{3.125\times 10^{22}}{2.90\times 10^{13}}

Number of iron atoms are present in each red blood cell = 1.077\times 10^9

Therefore, the number of iron atoms present in each red blood cell are, 1.077\times 10^9

6 0
3 years ago
HELP PLZ ITS A TEST.
tensa zangetsu [6.8K]

Answer:

The answer to your question is below

Explanation:

1 ) Which of the following is a chemical property.

A. Ability to become magnetic  this is wrong, it's a physical property

B. Ability to conduct electricity   this is wrong, it's a physical property

C. Ability to conduct heat   this is wrong, it's a physical property

D. Ability to react with acid This is the right answer

2 ) You heat two substances, A and B. Both substances change color. When cooled, substance B returns to its original color, but substance A does not. What most likely happened?.

A. Physical change occurred in both substances   This is wrong, a physial change only happens in substance B

B. A physical change occurred in substance A, and a chemical change occured in substance B.  This is wrong, a physical change occurred in substance B and a chemical change occurred in substance A.

C. A chemical change occurred in substance A, and a physical change occurred in substance B.  This is the right answer is exactly what happens

D. A chemical change occurred in both substances  This answer is wrong.

3 ) how many grams are in 2.5 pound sample? Express your answer in scientific notation with three significant figures. ( 1 pound= 453.592 grams).

Rule of three

    1 pound ------------------- 453.592 g

  2.5 pounds ---------------   x

  x = 2.5(453.592)/1

  x = 1133.98 g = 1.13 x 10³ g    letter D

7 0
3 years ago
Read 2 more answers
I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol
galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = \Delta H_f_{(I_2)}=62.438 kJ/mol

Enthalpy of formation of chlorine gas = \Delta H_f_{(Cl_2)}=0 kJ/mol

Enthalpy of formation of ICl gas = \Delta H_f_{(ICl)}=17.78 kJ/mol

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]

=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol

Enthaply change when 1.62 moles of iodine gas recast:

\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ

Entropy of the surrounding = \Delta S^o_{surr}=\frac{\Delta H}{T}

=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

4 0
3 years ago
Will mark as brainiest <br> Please help
Levart [38]

Answer:

  1. metal sulfate
  2. metal sulfate
  3. copper sulfate
  4. copper nitrate
  5. copper chloride
  6. copper phosphate
  7. hydrochloric acid, water
  8. Potassium, sulfuric acid, water

(Correct me if I am wrong)

4 0
3 years ago
Read 2 more answers
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