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Stella [2.4K]
3 years ago
15

carboxylic acid can react with an inorganic chloride to make an acid anhydride or acid chloride. Does it matter which chloride w

e react the carboxylic acid with or do we just pick one to use
Chemistry
2 answers:
Ket [755]3 years ago
8 0

Answer:

It doesn't matter which chloride

Explanation:

Because Carboxylic acids reacts with any of these inorganic chlorides such as PCl3, PCl5 and SOCl2 to form acid chloride as the major product, then the acid chloride further reacts to form acid anhydride

dalvyx [7]3 years ago
7 0

Answer:

Check Explanation.

Explanation:

Carboxylic acids undergo nucleophilic substitution reactions where the nucleophile (-OH) is substituted by another nucleophile.

In cases such as the reaction with inorganic chlorides, which are strong electrophiles, the partially negatively charged carbonyl oxygen (δ-) can act as a nucleophile and attack the electrophile.

So, the inorganic chlorides that Carboxylic acids react with are the ones with electrophilic centres. The ones with centres that have space to expand and accept electrons new pair of electrons.

Such inorganic chloride include SOCl₂, PCl₃ and PCl₅.

Hope this Helps!!!

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What causes ionic bonding between two atoms?
Marrrta [24]

Answer:

Ionic bonding happens when an atom of an element gives one or more of its electrons to the other element's atom..it usually takes place between metal and non metal atoms...like in NaCl, Na gives its valence electron to chlorine and completes its own octet. Chlorine accepts the electron and completes its own octet too...but now both the atoms have an opposing charge and hence they attract each other to form an IONIC bond.

Ionic bonds are the strongest of the bonds...here complete transfer of electrons takes place unlike covalent bonds.

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7 0
2 years ago
Air at 7S°F and14.6 though a cfm(cubic ft per minute) and the The flow rate is 48000 psia flows though a rectangular duct of Ix2
IgorLugansk [536]

Explanation:

The given data is as follows.

Air is at 75^{o}F and 14.6 psia.

\varepsilon = 0.00015 ft,     Flow rate, (Q) = 48000 ft^{3}/m

(a)  Formula to calculate hydraulic radius (r_{H}) is as follows.

              r_{H} = \frac{\text{free flow area}}{\text{wet perimeter}}

                          = \frac{2 \times 1}{2(1) + 2(2)}

                          = \frac{1}{3} ft

Formula for equivalent diameter is as follows.

                     D_{eq} = 4 \times r_{H}

                                    = 4 \times \frac{1}{3} ft  

                                    = \frac{4}{3} ft

(b)    Formula for velocity floe is as follows.

                         Q = VA

                     V = \frac{Q}{A}

                        = \frac{48000}{2 \times 1} ft/min

                        = 24000 ft/min

(c)   Formula to calculate Reynold's number is as follows.

         R_{e} = \frac{D \times V \times \rho}{\mu}

                   = \frac{\frac{4}{3} \times 24000 \times 0.0744}{0.0443}  (as \rho = 0.0744 lb/ft^{3} and \mu = 0.0443 lb/ft. hr)

                   = 53742.66 hr/min  

As 1 hr = 10 min. So, 53742.66 hr/min \times \frac{60 min}{1 hr}

                            = 3224559.6

(d)   Formula to calculate pressure drop (\Delta P) is as follows.

              \frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}

Putting the given values into the above formula as follows.

               \frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}

                      = \frac{4 \times 0.00015 \times 100 \times 0.0744 \times (24000)^{2}}{2 \times \frac{4}{3} \times {4}{3}}

                      = 6.238 lb/ft^{2}

5 0
3 years ago
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valentina_108 [34]

Answer:6.022 x 10^23 molecules

Explanation: Since one mole of any chemical compound always contains 6.022 x 10^23 molecules, you can calculate the number of molecules of any substance if you know its mass and its chemical formula.

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