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DochEvi [55]
3 years ago
8

How many ounces are in 0.442 L? Use dimensional analysis to

Chemistry
1 answer:
vovangra [49]3 years ago
3 0

Answer:

14.945798 in us fluid ounce

Explanation:

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I don't know what model you're referring to so I can't answer the question. However, upon researching, I found a similar problem. I posted it as an attached picture. Looking at the model, the amount of grams a herbivore eat each day corresponds to the arrow pointing inwards. Since the label says 4.0 g, <em>the answer is 4 g per day</em>.

8 0
3 years ago
The process of the classifying living thing is
jok3333 [9.3K]

Answer:

D. all of these

Explanation:

In the classification of organisms, they are placed into groups which they appropriately fit into.

All the choices given correctly shows the process of classifying organisms. This aspect of biology is described as taxonomy.

  • Based on characteristics of organisms, they are put into the same groups
  • Also, we can identify the related family and genus in which a discovered organism can be put into.
  • They phylogenetic relationship between organisms are important for classification.
7 0
3 years ago
Zn + 2 HCl --&gt; H2 + ZnCl2 If 1.70 g of Zn are reacted, how many grams of ZnCl2 can be created? Show work and process and I wi
Dovator [93]

Explanation:

first find the the number of moles of of zinc .

as the number of moles of zinc and ZnCl2 is same we can calculate the mass of ZnCl2.

6 0
3 years ago
A helium balloon with a volume of 550mL is cooled from 305 to 265K. The pressure on the gas is reduced from 0.45 atm to 0.25 atm
Aleksandr [31]

860 mL.

<h3>Explanation</h3>

Separate this process into two steps:

  1. Cool the balloon from 305 K to 265 K.
  2. Reduce the pressure on the balloon from 0.45 atm to 0.25 atm.

What would be the volume of the balloon after each step?

After Cooling the balloon at constant pressure:

By Charles's Law, the volume of a gas is directly related to its temperature in degrees Kelvins.

In other words,

\dfrac{V_2}{V_1} = \dfrac{T_2}{T_1},

where

  • V_1 and V_2 are volumes of the same gas.
  • T_1 and T_2 are the temperatures (in degrees Kelvins) of that gas.

Rearranging,

V_2 = V_1 \cdot \dfrac{T_2}{T_1}\\\phantom{V_2} = 550 \times \dfrac{265}{305}\\\phantom{V_2} = 478 \; \text{mL}.

The balloon ended up with a lower temperature. As a result, its volume drops: V_2 < V_1.

After reducing the pressure on the balloon at constant temperature:

By Boyle's Law, the volume of a gas is inversely proportional to the pressure on this gas.

In other words,

\dfrac{V_2}{V_1} = \dfrac{P_1}{P_2},

where

  • V_1 and V_2 are volumes of the same gas.
  • P_1 and P_2 are the pressures on this gas.

Rearranging,

V_2 = V_1 \cdot \dfrac{P_1}{P_2}\\\phantom{V_2} = 478 \times \dfrac{0.45}{0.25}\\\phantom{V_2} = 860 \;\text{mL}.

There's now less pressure on the balloon. As a result, the balloon will gain in volume: V_2 > V_1.

The final volume of the balloon will be 860 \; \text{mL}.

7 0
3 years ago
I need help pleaseee!!!!!!!! Fast
AfilCa [17]

Answer:

C is the correct answer

Explanation:

Hope this helps:)

4 0
3 years ago
Read 2 more answers
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