Answer: im assuming this is a z.oom?
Explanation:
Answer:
Explanation:
Molar ratio for Sg : FeS = 1:8
If there are 0.3 moles for Sg
Therefore, 0.3 × 8 =2.4 moles of FeS
Mass = Moles/ Mr
Mr of FeS = 56+32=88
So mass = 2.4/88
Mass= 0.027g
Answer:
Kc = 2.34 mol*L
Explanation:
The calculation of the Kc of a reaction is performed using the values of the concentrations of the participants in the equilibrium.
A + B ⇄ C + D
Kc = [C] * [D] / [A] * [B]
According to the reaction
Kc = [SO2]^2 * [O2]^2 / [SO3]^2
Knowing the 0.900 mol of SO3 is placed in a 2.00-L it means we have a 0.450 mol/L of SO3
0.450 --> 0 + 0 (Beginning of the reaction)
0.260 --> 0.260 + 0.130 (During the reaction)
0.190 --> 0.260 + 0.130 (Equilibrium of the reaction)
Kc = [0.260]^2 + [0.130]^2 / [0.190]^2
Kc = 2.34 mol*L
