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Elza [17]
3 years ago
13

Several rocks slide down a mountainside, each with the same velocity. Which rock will have the greatest momentum?

Physics
2 answers:
ValentinkaMS [17]3 years ago
4 0
The biggest rock, because it has more mass. More mass means that gravity is stronger on it than the other rocks, thus pulling it towards the center of the Earth more quickly, when on a slope.
snow_lady [41]3 years ago
4 0
The biggest rock because it has more mass contained and pushes more force against gravity
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6.P.2.1 Matter: Properties and Changes Notes
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Answer:

The __law__ conservation

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In exothermic/exergonic reactions, reactants have greater energy(Gibbs-Free Energy) than the products. This energy determines how much mechanical work a system can do
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3 years ago
The coefficient of performance of a residential heat pump is 1.6. Calculate the heating effect in kJ/s this heat pump will produ
Andre45 [30]

Answer:

Q_{H}=6.4kJ/s

Explanation:

Given data

Coefficient of performance of a residential heat pump=1.6

Electrical power P=4kW

Required

Heat Q

Solution

The rate of heat produced is given as

Q_{H}=COP_{HP}Win\\

Substitute the given values

So

Q_{H}=4kW*1.6\\Q_{H}=6.4kJ/s

6 0
3 years ago
A heavy box is in the back of a truck. the truck is accelerating to the right. apply your analysis to the box.a) draw a motion d
Andru [333]

Explanation :

It is given that, a heavy box is in the back of a truck and the truck is accelerating to the right.

The description is shown in<em> figure 1</em>. Here, the forces that act on both box and the truck are the normal force, the frictional force and their weight mg.

The free body diagram is shown in <em>figure 2</em>. This shows the total forces            ( F = ma )acting on the truck. As a result, the truck will move in a forward direction.

Hence, this is the required explanation.

5 0
3 years ago
Read 2 more answers
Two point charges of 60.0 C and -12.0 C are separated by a distance of 20.0 cm. A 7.00 C charge is placed midway between these t
iogann1982 [59]

Answer:

4.5\times 10^{14} N

Explanation:

q_1=60 C

q_2=-12 C

q_3=7 C

Distance between q1 and q2,d=20 cm

r=\frac{d}{2}=\frac{20}{2}=10 cm=10\times 10^{-2} m

1m =100 cm

Electric force on charge q3 due to charge q1

F_1=\frac{kq_1q_3}{r^2}=\frac{9\times 10^9\times 60\times 7}{(10\times 10^{-2})^2} (away from q1)

Electric force on charge q3 due to charge q2

F_2=\frac{kq_2q_3}{r^2}=\frac{9\times 10^9\times 12\times 7}{(10\times 10^{-2})^2}(attract toward q2)

Net force=F=F_1+F_2

F=\frac{9\times 10^9\times 60\times 7}{(10\times 10^{-2})^2}+\frac{9\times 10^9\times 12\times 7}{(10\times 10^{-2})^2}

F=\frac{9\times 10^9\times 7}{(10\times 10^{-2})^2}(60+12)

F=4.5\times 10^{14} N

5 0
4 years ago
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