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Finger [1]
3 years ago
13

A rock is thrown vertically upward from the ground, with an initial velocity of 64 ft/sec. Its position function is s(t) = –16t2

+ 64t. What is its velocity in ft/sec when it hits the ground?
Physics
1 answer:
cestrela7 [59]3 years ago
3 0
<h2>Velocity of rock when it hits the ground is -64 ft/s</h2>

Explanation:

Its position function is s(t) = –16t² + 64t

When it reaches back ground s(t) = 0 ft

Substituting

                s(t) = –16t² + 64t = 0

                          t² - 4t = 0

                           t²  = 4t

                           t =4 seconds

Now we need to find velocity when it reaches ground, that is velocity after 4 seconds.

Differentiating s(t) equation

                   v(t) = -32t+64

            Substituting t = 4 seconds

                  v(4) = -32 x 4+64  = -64 ft/s

Velocity of rock when it hits the ground is -64 ft/s

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allsm [11]

To develop this problem it is necessary to apply the concepts related to the Dopler effect.

The equation is defined by

f_i = f_0 \frac{c}{c+v}

Where

f_h= Approaching velocities

f_i= Receding velocities

c = Speed of sound

v = Emitter speed

And

f_h = f_0 \frac{c}{c+v}

Therefore using the values given we can find the velocity through,

\frac{f_h}{f_0}=\frac{c-v}{c+v}

v = c(\frac{f_h-f_i}{f_h+f_i})

Assuming the ratio above, we can use any f_h and f_i with the ratio 2.4 to 1

v = 353(\frac{2.4-1}{2.4+1})

v = 145.35m/s

Therefore the cars goes to 145.3m/s

7 0
3 years ago
A hockey puck is sliding across a frozen pond with an initial speed of 9.5 m/s. It comes to rest after sliding a distance of 37.
Bond [772]

Answer:

<h3>The coefficient of kinetic friction between the puck and the ice is \mu _{k} = 0.12</h3>

Explanation:

Given :

Initial speed  v_{o} = 9.5 \frac{m}{s}

Displacement x = 37.4 m

From the kinematics equation,

  v^{2} - v^{2} _{o}  = 2ax

Where v^{2}   = final velocity, in our example it is zero (v =0), a = acceleration.

   a =- \frac{90.25}{ 2 \times 37.4}

   a =- 1.21 \frac{m}{s^{2} }

From the formula of friction,

  F =- \mu _{k } N

Minus sign represent friction is oppose the motion

Where N = mg ( normal reaction force )

 ma = -\mu _{k}  m g                                                  ( ∵ g = 9.8 \frac{m}{s^{2} } )

So coefficient of friction,

 \mu_{k} = \frac{1.21}{9.8}

 \mu_{k} = 0.12

Therefore, the coefficient of kinetic friction between the puck and the ice is  \mu _{k} = 0.12 .

4 0
3 years ago
Instruction Active
nikklg [1K]

If the distance between two objects decrease and the masses of the objects remain the same, then the force of gravity between the two objects

<u>Answer:</u>

increases

Explanation:

The formula of gravitational force is given as:

F=G Mm/r^2

G = gravitational constant

M, m = Masses of two different objects in which the force is acting.

r = distance between both the objects.

As we can see from the formula that the force of gravity is inversely proportional to the square of the distance between both objects.

When the distance between both objects with the same masses decreases the gravitational force between them increases. Hence the correct answer is option B.

Illamends had the exact same answer from a similar question. Credit goes to her

4 0
2 years ago
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jekas [21]

Answer:

2.5 x 10⁻⁹ m

Explanation:

E = Energy of photon = 500 eV = 500 x 1.6 x 10⁻¹⁹ J

c = speed of photon = 3 x 10⁸ m/s

λ = wavelength of photon = ?

Energy of photon is given as

E = \frac{hc}{\lambda }

inserting the values

500\times 1.6\times 10^{-19} = \frac{(6.63\times 10^{-34})(3\times 10^{8})}{\lambda }

λ = 2.5 x 10⁻⁹ m

5 0
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tekilochka [14]

Answer:

c

Explanation:

this is because you move ( kinetic energy) your hands and clap the other person's hand, you will definitely hear sound right.

3 0
3 years ago
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