Answer:
The velocity must be reduced to one third to stay on the road
Explanation:
The sideways force that friction must resist comes from the centrifugal acceleration due to the turn.
fc=mv2Rfc=mv2R
the frictional force is given by
ff=μmgff=μmg where μμ is the static friction coefficient
if the car is not to skid
fc≤fffc≤ff so
mv2R≤μmgmv2R≤μmg
v≤μgR−−−−√v≤μgR
thus vv varies as the square root of μμ
so if μμ is reduced by 9, vv must be reduced by 9–√=39=3
and thus the speed must be reduced to<u> 26</u> m/s
3
Answer:
spring 1 has less potential energy
Explanation:
since spring 2 is clampped down further it will have a greater effect but since sping 1 is barely clamped down it wont show as much energy
Answer:
sorry I don't understand this language
Let k be the spring constant. Then you have
188=k*21.8
k=188/21.8=8.62,
In the second part you use
m g= k x
x=m g/k= 38/8.62=4.4cm
4.4 cm is the answer
Answer:
Time = 12.06 seconds
Explanation:
Given the following data;
Power = 2.984 KW = 2984 Watts
Workdone = 3.60 × 10^4 J = 36000 J
To find the time;
Power = workdone/time
Time = workdone/power
Time = 36000/2984
Time = 12.06 seconds
Therefore, the engine would have to run for 12.06 seconds.
