Question

A survey of college students found that 56 percent live in a campus residence hall and 62 percent participate in a meal program and 42 percent do both what is the probability that a randomly selected student either lives or eats on campus

Answer 1

Answer:

The percent of people, who either lives or eats on campus is 34 %.

Step-by-step explanation:

Let the total number of people be 100.

Let set A be people who live in campus = 56

Let set B be people who participate in meal = 62

Let set C(A∩B) be people who do both = 42

According to set theory,

(A∪B) = A + B - (A∩B) = 56 + 62 - 42 = 76

Then either lives or eats is given by,

= (A∪B)-(A∩B) = 76 - 42 = 34

Thus, the percent of people, who either lives or eats on campus is 34 %.