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sergeinik [125]
3 years ago
11

A survey of college students found that 56 percent live in a campus residence hall and 62 percent participate in a meal program

and 42 percent do both what is the probability that a randomly selected student either lives or eats on campus
Mathematics
1 answer:
Slav-nsk [51]3 years ago
5 0

Answer:

The percent of people, who either lives or eats on campus is 34 %.

Step-by-step explanation:

Let the total number of people be 100.

<em>Let set A be people who live in campus =</em><em> 56</em>

<em>Let set B be people who participate in meal = </em><em>62</em>

<em>Let set C(A∩B) be people who do both = </em><em>42</em>

According to set theory,

(A∪B) = A + B - (A∩B) = 56 + 62 - 42 = 76

Then either lives or eats is given by,

= (A∪B)-(A∩B) = 76 - 42 = 34

Thus, the percent of people, who either lives or eats on campus is 34 %.

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