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3 years ago

Help Please I put 70 pts on this

Mathematics

2 answers:

Gwar [14]3 years ago

8 0

Answer: A) intercepts: zero profit; maximum: maximum profit. increasing: x < 4; decreasing x > 4

B) average slope: ≈50, about $50 increased profit for each $1 increase in price.

Step-by-step explanation:

A) The vertical axis of the graph represents profit, so the x-intercepts represent prices that produce zero profit. The maximum value of the graph is the maximum profit that can be obtained for any price.

The function is increasing for all prices below the one producing maximum profit (x < 4). The function is decreasing for all prices above the one producing maximum profit (x > 4). Obviously profit is increasing with price for x < 4, and is decreasing with price for x > 4.

B) We read the value of f(1) from the graph to be about 120, so the average rate of change is about ...

(f(4) -f(1))/(4 -1) = (270 -120)/(3) = 50

The average rate of change from x=1 to x=4 is about 50.* This means profit will increase on average $50 for each $1 increase in price in that interval.

_____

* If we take the peak profit to be $270, we can write f(x) as ...

f(x) = 16.875x(x -8)

Then f(1) = 118.125 and the average rate of change is 50.625. For the purpose here, we judge the extra precision to be pointless.

Step-by-step explanation:

sertanlavr [38]3 years ago

7 0

Answer:

Part C:The constraint of the domain is 0 < x < 8

Step-by-step explanation:

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we conclude that at 5:00 p.m. there are 8 more inches of snow than at 8:00 a.m.

<h3>How many more inches of snow were on the ground at 5:00 p.m. than at 8:00 a.m.?</h3>

We know that at 8:00 a.m. there were t inches of snow in the ground.

At 5:00 p.m. there were 3t inches of snow in the ground.

Then the difference between the heights of the snow is:

3t- t = 2t

And we know that at 5:00 p.m. there were 12 inches of snow then we can solve the linear equation for t:

3t = 12in

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If you want to learn more about linear equations:

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2 years ago

Solve for n.<br> Q=5n+5z

kirill115 [55]

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3 years ago

Read 2 more answers

the area of a rectangle city park is 25/54 sqaure miles. the length of the park is 5/9 mile. what is the width in miles of the p

andreyandreev [35.5K]

A = lw

Plug in what we know:

25/54 = (5/9)w

Divide 5/9 to both sides or multiply by its reciprocal, 9/5:

25/54 * 9/5 = w

Multiply the numerators and denominators together:

225/270 = w

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3 years ago

A random sample of 102 full-grown lobsters had a mean weight of 16 ounces and a standard deviation of 3.4 ounces. Construct a 98

pshichka [43]

Answer:

The best point estimate for a confidence interval estimating the population μ is 16 ounces.

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The best point estimate for a confidence interval estimating the population μ is

The sample mean, so 16 ounces.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 102 - 1 = 101

98% confidence interval

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The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

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2 years ago

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Morgarella [4.7K]

Answer:

The correct product is 6,252.

I don't know what Dan did wrong lol

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3 years ago