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OleMash [197]
3 years ago
15

Acids,basesandcombustion

Chemistry
1 answer:
VashaNatasha [74]3 years ago
3 0

Answer:

tetraoxosulphate 6 acid

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Copper(II) oxide reacts with carbon when heated.
Alexus [3.1K]

Answer:

the fourth one or the first, but I wouldn't say I'm completely sure.

Explanation:

8 0
3 years ago
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A beaker contains 318 mL
katovenus [111]

Answer:

3.97 M

Explanation:

Given data:

Initial volume V₁  = 318 mL

Initial molarity M₁ = 5.75 M

New volume V₂=  461 mL

New concentration M₂= ?

Solution:

New volume V₂= 143 mL+ 318 mL

New volume V₂= 461 mL

Formula:

M₁V₁  = M₂V₂

M₂ = M₁V₁ / V₂

M₂ = 5.75 M × 318 mL / 461 mL

M₂ = 1828.5 M. mL/ 461 mL

M₂ = 3.97 M

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Magnesium reacts with nitrogen oxide to form...?
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It forms magnesium nitride
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When an atom of uranium-235 is bombarded with neutrons, it splits into smaller nuclei and produces a great amount of energy. thi
lilavasa [31]
It's nuclear fission: the splitting of the nucleus
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3 years ago
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The molar mass of a certain gas is 49 g. What is the density of the gas in g/L at STP?
snow_tiger [21]

Answer:

\boxed{\text{2.2 g/L}}

Explanation:

We can use the Ideal Gas Law to calculate the density of the gas.

   pV = nRT

      n = m/M           Substitute for n

   pV = (m/M)RT     Multiply both sides by M

pVM = mRT            Divide both sides by V

  pM = (m/V) RT

     ρ = m/V             Substitute for m/V

 pM = ρRT              Divide each side by RT

\rho = \frac{pM }{RT}

Data:

p = 1.00 bar

M = 49 g/mol

R = 0.083 14 bar·L·K⁻¹mol⁻¹

T = 0 °C = 273.15 K

Calculation:

ρ = (1.00 × 49)/(0.083 14 × 273.15) = 2.2 g/L

The density of the gas is \boxed{\text{2.2 g/L}}.

8 0
4 years ago
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