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kirill115 [55]
3 years ago
10

What happens at the particle level during a chemical reaction?

Chemistry
1 answer:
larisa86 [58]3 years ago
4 0

Answer:

Reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.RT

Explanation:

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Find the wavelength of the electromagnetic radiation with a frequency of 3x10^-18Hz (Show Work)
aalyn [17]

Answer:

λ   = 1×10²⁶m

Explanation:

Given data:

Wavelength of radiation =  ?

Frequency of radiation = 3×10⁻¹⁸Hz

Solution:

Formula:

c = f × λ

c = speed of wave = 3×10⁸ m/s

by putting values,

3×10⁸ m/s =   3×10⁻¹⁸Hz  × λ

λ  =  3×10⁸ m/s /  3×10⁻¹⁸s⁻¹

λ   = 1×10²⁶m

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3 years ago
Answer these 2 questions FAST PLEASEE!!! I WILL GIVE BRAINLIEST AND GIVE EXTRA POINTS
madreJ [45]

Answer:

q5: b

q6: a

Explanation:

7 0
2 years ago
Write the chemical formulas for the ionic compound vanadium (v) oxide
olya-2409 [2.1K]
V2O5 is the formula. Vanadium has a charge of +5 and oxygen is -2, so to make them equal, you need to double the vanadium charge and multiply the oxygen charge by 5
5 0
3 years ago
Calculate the theoretical yield of 1-bromobutane; base your calculations on using 1.0 g of 1-butanol (as the limiting reagent).
Tomtit [17]

C₄H₉OH + HBr = C₄H₉Br + H2O

Δmole of alcohol gives 1 mole of bromobutanol

HBr is in excess, so the yield of the product is limited by the alcohol

Wt. of 1 butanol = 18

Molar mass of the butanol = 74.12 g/mole

Moles of the alcohol = 1/74.12 = 0.01349 moles

So, moles of bromobutane = 0.01349 moles

Molar mass of C₄H₉Br = 137.018 g/moles

So, theoretical mass of bromobutane is = 0.01349 × 137.0.18

= 1.85 g


6 0
3 years ago
Read 2 more answers
Can somebody help me, please!
zavuch27 [327]

Answer:

Rubidium-85=61.2

Rubidium-87=24.36

Atomic Mass=85.56 amu

Explanation:

To find the atomic mass, we must multiply the masses of the isotope by the percent abundance, then add.

<u>Rubidium-85 </u>

This isotope has an abundance of 72%.

Convert 72% to a decimal. Divide by 100 or move the decimal two places to the left.

  • 72/100= 0.72      or        72.0 --> 7.2 ---> 0.72

Multiply the mass of the isotope, which is 85, by the abundance as a decimal.

  • mass * decimal abundance= 85* 0.72= 61.2

Rubidium-85=61.2

<u>Rubidium-87</u>

This isotope has an abundance of 28%.

Convert 28% to a decimal. Divide by 100 or move the decimal two places to the left.

  • 28/100= 0.28       or        28.0 --> 2.8 ---> 0.28

Multiply the mass of the isotope, which is 87, by the abundance as a decimal.

  • mass * decimal abundance= 87* 0.28= 24.36

Rubidium-87=24.36

<u>Atomic Mass of Rubidium:</u>

Add the two numbers together.

  • Rb-85 (61.2) and Rb-87 (24.36)
  • 61.2+24.36=85.56 amu
4 0
3 years ago
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