The concentration of the sodium chloride would be 0.082 M
<h3>Stoichiometric calculations</h3>
From the equation of the reaction, the ratio of AgCl produced to NaCl required is 1:1.
Mole of 46.6 g AgCl produced = 46.6/143.32 = 0.325 moles
Equivalent mole of NaCl = 0.325 moles.
Molarity of 0.325 moles, 3.95 L NaCl = mole/volume = 0.325/3.95 = 0.082 M
More on stoichiometric calculations can be found here: brainly.com/question/27287858
#SPJ1
Answer: 190 g of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide.
Explanation:
The balanced chemical reaction is;
is the limiting reagent as it limits the formation of product and 
is the excess reagent.
According to stoichiometry :
1 mole of produces = 1 mole of 
Thus 2 moles of will produce=
of
Mass of 
Thus 190 g of magnesium chloride can be produced by reacting 2 moles of chlorine gas with excess magnesium bromide
Answer:
69
Explanation:
hey u said what I said didusbevehdysg
Answer: 0.0508mL
Explanation: Using the basic formula that states: C acid * V acid = C base * V base. we have:0.568 * 17.88 = 20 * C base.
therefore concentration of the base is 1.0156/20 = 0.0508 mL
