Answer: 484
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Work Shown:
First let's compute f(2). We replace every x with 2 and then use PEMDAS to simplify
f(x) = -x^4 + 5x - 4x^2
f(2) = -(2)^4 + 5(2) - 4(2)^2
f(2) = -16 + 5(2) - 4(4)
f(2) = -16 + 10 - 16
f(2) = -6 - 16
f(2) = -22
Then we square this result to find the value of ![[ f(2) ]^2](https://tex.z-dn.net/?f=%5B%20f%282%29%20%5D%5E2)
![f(2) = -22\\\\\left[ f(2) \right]^2 = [ -22 ]^2\\\\\left[ f(2) \right]^2 = 484](https://tex.z-dn.net/?f=f%282%29%20%3D%20-22%5C%5C%5C%5C%5Cleft%5B%20f%282%29%20%5Cright%5D%5E2%20%3D%20%5B%20-22%20%5D%5E2%5C%5C%5C%5C%5Cleft%5B%20f%282%29%20%5Cright%5D%5E2%20%3D%20484)
There isn’t an answer because you haven’t provided us enough data
Answer:
First parabola's vertex is (-2,2), which is a minimum.
Second parabola's vertex is (3,2), which is a maximum.
Step-by-step explanation:
Simply, a vertex of a quadratic is a graph's turning point.
The maximum and minimum can be identified by seeing if the graph curves up or down.
Maximum occurs when your graph is facing down.
Minimum occurs when your graph is facing up.
