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Paraphin [41]
3 years ago
11

A 9 foot flagpole cast a shadow 6 feet long, and at the same time a nearby tree cast a shadow 14 feet long. What is x the hight

of the tree.

Mathematics
2 answers:
frosja888 [35]3 years ago
8 0
It is 17 ft long because for the flagpole the shadow was 3 feet shorter then the actual height of the flag pole, so for the tree the shadow is 14 ft so you would add 3 ft and that equals 17
Wittaler [7]3 years ago
6 0
I think it is 17, hope this can help someone
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Step-by-step explanation:

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If m&lt;ECD is six less than five times m&lt;BCE. and m&lt;BCD = 162°, find each measure.(Sorry bout using the wrong signs, but
tia_tia [17]

Answer:

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Step-by-step explanation:

* Lets explain how to solve the problem

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- m∠ECD is six less than five times m∠BCE

- That means when we multiply measure of angle BCE by five and

 then subtract six from this product the answer will be the measure

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∴ m∠ECD = 5 m∠BCE - 6 ⇒ (1)

∵ m∠BCD = m∠BCE + m∠ECD

∵ m∠BCD = 162°

∴ m∠BCE + m∠ECD = 162 ⇒ (2)

- Substitute equation (1) in equation (2) to replace angle ECD by

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∴ m∠BCE + (5 m∠BCE - 6) = 162

- Add the like terms

∴ 6 m∠BCE - 6 = 162

- Add 6 to both sides

∴ 6 m∠BCE = 168

- Divide both sides by 6

∴ m∠BCE = 28°

- Substitute the measure of angle BCE in equation (1) to find the

  measure of angle ECD

∵ m∠ECD = 5 m∠BCE - 6

∵ m∠BCE = 28°

∴ m∠ECD = 5(28) - 6 = 140 - 6 = 134°

* m∠BCE = 28° and m∠ECD = 134°

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A manufacturer cuts squares from the corners of a rectangular plece of sheet metal that measures 2 inches by 7 inches (see Figur
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Answer:

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see the attached figure to better understand the problem

we know that

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substitute

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Convert to expanded form

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Graph the cubic equation

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