1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MAXImum [283]
3 years ago
8

What is the length of MN

Mathematics
2 answers:
MakcuM [25]3 years ago
7 0
It is an isosceles triangle and therefore

3x = x + 10
2x = 10
x = 5
Since x = 5 and MN = x + 10 then,
MN = 15.

Dafna1 [17]3 years ago
5 0
Because this is an isosceles triangle, 3x = x + 10.  Thus, 2x + 10 and x = 5.

With x=5, MN has the length 5+10, or 15.
You might be interested in
3/5 - 1/2 this is all I need right now
Vlada [557]

The correct answer is

\frac{1}{10}

3 0
3 years ago
Read 2 more answers
Customers arrive at a service facility according to a Poisson process of rate λ customers/hour. Let X(t) be the number of custom
mash [69]

Answer:

Step-by-step explanation:

Given that:

X(t) = be the number of customers that have arrived up to time t.

W_1,W_2... = the successive arrival times of the customers.

(a)

Then; we can Determine the conditional mean E[W1|X(t)=2] as follows;

E(W_!|X(t)=2) = \int\limits^t_0 {X} ( \dfrac{d}{dx}P(X(s) \geq 1 |X(t) =2))

= 1- P (X(s) \leq 0|X(t) = 2) \\ \\ = 1 - \dfrac{P(X(s) \leq 0 , X(t) =2) }{P(X(t) =2)}

=  1 - \dfrac{P(X(s) \leq 0 , 1 \leq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}

=  1 - \dfrac{P(X(s) \leq 0 ,P((3 \eq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}

Now P(X(s) \leq 0) = P(X(s) = 0)

(b)  We can Determine the conditional mean E[W3|X(t)=5] as follows;

E(W_1|X(t) =2 ) = \int\limits^t_0 X (\dfrac{d}{dx}P(X(s) \geq 3 |X(t) =5 )) \\ \\  = 1- P (X(s) \leq 2 | X (t) = 5 )  \\ \\ = 1 - \dfrac{P (X(s) \leq 2, X(t) = 5 }{P(X(t) = 5)} \\ \\ = 1 - \dfrac{P (X(s) \LEQ 2, 3 (t) - X(s) \leq 5 )}{P(X(t) = 2)}

Now; P (X(s) \leq 2 ) = P(X(s) = 0 ) + P(X(s) = 1) + P(X(s) = 2)

(c) Determine the conditional probability density function for W2, given that X(t)=5.

So ; the conditional probability density function of W_2 given that  X(t)=5 is:

f_{W_2|X(t)=5}}= (W_2|X(t) = 5) \\ \\ =\dfrac{d}{ds}P(W_2 \leq s | X(t) =5 )  \\ \\  = \dfrac{d}{ds}P(X(s) \geq 2 | X(t) = 5)

7 0
3 years ago
8 The sum of four consecutive odd integers is 96. What are the numbers?
grigory [225]

Answer:The sum of all is 21+23+25+27 = 96.

Step-by-step explanation:

5 0
2 years ago
(x-1)^2+(2-x)^2-3(x-5)*(x-5)
Natali5045456 [20]

Answer:

-x^2+24x-70

Step-by-step explanation:

(x-1)^2+(2-x)^2-3(x-5)*(x-5)\\=> (x - 1)^2 + (2 - x)^2 - 3(x - 5)^2\\=> x^2 - 2x + 1 + 4 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 2x + 5 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 6x + 5 + x^2 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x^2 - 10x + 25)\\=> 2x^2 - 6x+5  - 3x^2+30x-75\\=> -x^2 - 6x + 5 + 30x - 75\\=> -x^2 + 24x + 5-75\\=> -x^2+24x-70

Formula used =

(a-b)^2 = a^2+ 2ab + b^2

8 0
2 years ago
Find the value of a²+b <br> if...<br> a=-2 and b=5
Nana76 [90]

Answer:

9

Step-by-step explanation:

a²+b

Substituting values,

=> (-2)^2+5

=> 4 + 5

=> 9

4 0
3 years ago
Read 2 more answers
Other questions:
  • PLEASE ANSWER QUICK!!!
    8·1 answer
  • Evelina took 50 people fishing each day last week. The table shows the number of fish the group caught each day.
    11·1 answer
  • Please help me idk this ????
    11·2 answers
  • HELPPPP I need help with this question!!!!
    6·1 answer
  • Which sentence is Correct and please take your time !!!
    7·2 answers
  • HELPPPP!!! PLEASEEEE I’M FAILING ALGEBRA AND I NEED HELP WITH THIS QUESTION
    13·2 answers
  • The figure above shows the graph of the function g(a)=0, what is the value of a?
    14·1 answer
  • A boy pushes a bike with 5 newtons up a hill that is 300 meter long. How much work does he do?
    7·1 answer
  • Pls help me with is problem
    14·1 answer
  • an architect is designibg a tapered office tower where rge ground floor us the largwst amd the floor space is reduced by 6.3% pe
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!