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3 years ago

12

Using compatible numbers what is 231 divided by 34

2 answers:

hichkok12 [17]3 years ago

7 0

The compatible number is 7 (seven)

svp [43]3 years ago

4 0

33 and 7 since those are whole numbers

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3. Continue the pattern with 4 fifths.

Elenna [48]

Answer:

I don’t have enough context clues to answer your question I’m afraid

Step-by-step explanation:

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3 years ago

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Ron what to make a rectangle basketball court if the length is 4 whole number 3/4 yd and the width is 3 whole number is 2/5 yd.

hoa [83]

A = L * W

A = 4 3/4 * 3 2/5.....turn them into improper fractions
A = 19/4 * 17/5
A = 323/20 or 16 3/20 yds^2 <==

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3 years ago

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masya89 [10]

Tbh I can’t see that

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2 years ago

Use substitution to solve the following system of linear equations and fill in the following blanks:

marissa [1.9K]

Answer:

$x=-4$

$y=3$

$z=-5$

Step-by-step explanation:

<u>Given:</u>

$x+y+z=-6$

$x-6y-7z=-29$

$-7y-5z=4$

<u>Solve for </u> $x$ <u> in the 1st equation:</u>

$x+y+z=-6$

$x+y=-z-6$

$x=-y-z-6$

<u>Substitute the value of </u> $x$ <u> into the 2nd equation and solve for </u> $z$ <u>:</u>

$x-6y-7z=-29$

$(-y-z-6)-6y-7=-29$

$-7y-z-13=-29$

$-7y-z=-16$

$-z=-16+7y$

$z=16-7y$

<u>Substitute the value of </u> $z$ <u> into the 3rd equation and solve for </u> $y$ <u>:</u>

$-7y-5z=4$

$-7y-5(16-7y)=4$

$-7y-80+35y=4$

$28y-80=4$

$28y=84$

$y=3$

<u>Plug </u> $y=3$ <u> into the solved expression for </u> $z$ <u> and evaluate to solve for </u> $z$ <u>:</u>

$z=16-7(3)$

$z=16-21$

$z=-5$

<u>Plug </u> $z=-5$ <u> into the solved expression for </u> $x$ <u> and evaluate to solve for </u> $x$ <u>:</u>

$x=-(3)-(-5)-6$

$x=-3+5-6$

$x=2-6$

$x=-4$

Therefore:

$x=-4$

$y=3$

$z=-5$

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3 years ago

Two quantities, x and y, are directly proportional. If x is doubled, what happens to y?

vagabundo [1.1K]

Answer:

y is also doubled.

Step-by-step explanation:

Direct proportionality between $x$ and $y$ means that

$y \propto x$

or

$y=cx$ ,

which indicates a linear relationship between $x$ and $y$ because they are related by a constant.

Therefore, if x is doubled, then the new value of $y$ is $y_{new}$

$y_{new}=c(2x)$

$y_{new}=2(cx)$

$y_{new}=2y$

The new value of $y$ is 2 times the previous; therefore, $y$ is doubled as $x$ is doubled.

7 0

3 years ago

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