1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
timurjin [86]
3 years ago
11

Simplify the sum. d^2-9d+20/d^2-3d-10 plus d^2-2d-8/d^2+4d-32

Mathematics
2 answers:
BabaBlast [244]3 years ago
7 0

Answer:

Hence, the final result after simplification is:

\dfrac{2d^2+8d-28}{d^2+10d+16}

Step-by-step explanation:

We have to simplify the sum:

d^2-9d+20/d^2-3d-10 plus d^2-2d-8/d^2+4d-32 i.e.

\dfrac{d^2-9d+20}{d^2-3d-10}+\dfrac{d^2-2d-8}{d^2+4d-32}

now we will apply the method of splitting the middle term in each of the polynomial terms in the numerator and denominator to obtain:

=\dfrac{d^2-5d-4d+20}{d^2-5d+2d-10}+\dfrac{d^2-4d+2d-8}{d^2+8d-4d-32}\\\\\\\\=\dfrac{d(d-5)-4(d-5)}{d(d-5)+2(d-5)}+\dfrac{d(d-4)+2(d-4)}{d(d+8)-4(d+8)}\\\\\\=\dfrac{(d-4)(d-5)}{(d+2)(d-5)}+\dfrac{(d+2)(d-4)}{(d+8)(d-4)}\\\\\\=\dfrac{d-4}{d+2}+\dfrac{d+2}{d+8}\\\\\\=\dfrac{(d-4)(d+8)+(d+2)(d+2)}{(d+2)(d+8)}

which on solving gives us the final result as:

\dfrac{2d^2+8d-28}{d^2+10d+16}

dimaraw [331]3 years ago
3 0
For this case what you should do is follow the following steps:
 1) factorize numerator and denominator of both expressions.
 2) cancel similar terms
 3) add both fractions by cross product
 4) Rewrite the numerator and denominator.
 Answer:
 
See attached image.

You might be interested in
Terday. Priya successfully made 6 free throws. Today, she made 75% as
tatuchka [14]

Answer:

10

Step-by-step explanation:

Yesterday, Priya successfully made 6 free throws.

Today, she made 75% as many as yesterday.

We are asked to calculate the number of successful free throws that Priya made today.

So, the number will be 6 (1 + \frac{75}{100} ) = 10.5.

Since it is the number of successful free throws, so it will be 10 throws. ( Answer )  

4 0
3 years ago
2x^2-21x-36. Can someone help me out?
sergeinik [125]
-752<span>thatswhat the answer should be
</span>
8 0
3 years ago
Read 2 more answers
Solve equation. <br><br> X^2-4x-12 = 0
ser-zykov [4K]

Answer:

Step-by-step explanation:

x2 - 4x - 12 = 0

x2 - 6x + 2x - 12= 0

x(x - 6) + 2(x - 6) = 0

x + 2 = 0

x = - 2

x - 6 = 0

x = 6

5 0
4 years ago
What is the slope-intercept form of the equation y - 7= -5/2(x+4)
GREYUIT [131]
The first thing I would probably do is distribute (multiply) the -5/2 into the parenthesis:

= (-5/2)x + (-20/2)

Notice how I am not putting the x into the fraction. This is to make it easier to see the slope-intercept form.

Lets simplify the (-20/2) and then add 7 to both sides:

y - 7 = (-5/2)x - 10

y = (-5/2)x - 3

Your answer would then be:

y = (-5/2)x - 3

y = mx + b

Since it is now in the requested format.
4 0
3 years ago
Simplify this expression.<br>9 + 3 x 2​
adell [148]

Answer: 9+(3)(2)

=15

Step-by-step explanation:

9+(3)(2)

=9+6

=15

3 0
3 years ago
Read 2 more answers
Other questions:
  • On the first day, a company has 64 orders for shipping crates on backorder. Every day customers order 18 more shipping crates. I
    11·1 answer
  • Graph the following lines and write the equation in slope-intercept form. Through the point (2,−4) with y-intercept of −2.
    11·1 answer
  • What is 13 - x = -7 what is x in this equation
    8·2 answers
  • 6 twentieth 2 eights=
    15·1 answer
  • Mr.Jacobs has a $200 budget for school supplies. He purchased 12 reams of printer paper for $4 each and six packs of dry-erase m
    10·1 answer
  • Can someone please help me
    11·1 answer
  • For each of these lists of integers, provide a simple formula orrule that generates the terms of an integer sequence that begins
    13·1 answer
  • ....................
    11·2 answers
  • Find the volume of the cylinder.
    9·1 answer
  • PLEASE HELP ME I NEED THIS IN 15 MINUTES!!!
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!