This is what is known as a double replacement reaction. The two parts of each molecule separate and recombine to form two new compounds. For instance, $Al_2(SiO_3)_3$ separates into $Al_2$ and $(SiO_3)_3$ , while $NaOH$ separates into $Na$ and $OH$ , and then they recombine with the other compound.

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7 0

3 years ago

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PLEASE HELP CHEMISTRY QUESTION (picture attached)

Anastasy [175]

Answer:

It is called a salt bridge

8 0

2 years ago

An 8.42 g piece of metal with a specific heat of 1.020 J g-1 k-1 wasn't heated to an unknown temperature. The metal was then pla

ANTONII [103]

Answer:

$T = 61.344\,^{\textdegree}C$

Explanation:

The heat received by water is equal to the heat rejected by the piece of metal. That is to say:

$-Q_{piece} = Q_{water}$

$(8.42\,g) \cdot \left(1.020\,\frac{J}{g\cdot ^{\textdegree}C} \right) \cdot (T - 20.40\,^{\textdegree}C)= (44.2\,g)\cdot \left(4.187\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (20.40\,^{\textdegree}C-18.50\,^{\textdegree}C)$

$\left(8.588\,\frac{J}{^{\textdegree}C} \right)\cdot (T-20.40\,^{\textdegree}C) = 351.624\,J$

The initial temperature of the piece of metal is:

$T = 61.344\,^{\textdegree}C$

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3 years ago

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