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Maurinko [17]
3 years ago
9

What is the mole fraction of ethanol in a solution made by dissolving 29.2 g of ethanol, C2H5OH, in 53.6 g of water?

Chemistry
1 answer:
ANEK [815]3 years ago
4 0

Answer:

Mole fraction ethanol = 0.175

Explanation:

Mole fraction ethanol = Moles of ethanol / Total moles

Total moles = moles of ethanol + moles of water.

Moles of ethanol → 29.2 g . 1 mol / 46 g = 0.635 moles

Moles of water → 53.6 g . 1 mol / 18 g = 2.98 moles

Total moles → 0.635 mol + 2.98 mol = 3.615 moles

Mole fraction ethanol = 0.635 / 3.615 = 0.175

<u>Remember</u>: Mole fraction has no units

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Rolls of foil are 302 mm wide and 0.018 mm thick. (The density of foil is 2.7 g/cm3 .)
Kruka [31]

Answer:

The length of foil will be 8107.81 cm or 81.7081 m.

Explanation:

Given data:

Width of roll of foil = 302 mm

Height or thickness = 0.018 mm

Density of foil = 2.7 g/cm³

Mass of foil = 1.19 Kg

Length of foil = ?

Solution:

d = m/ v

v = length (l) × width (w) × height (h)

First of we will convert the Kg into gram and mm into cm.

one Kg = 1000 g

1.19 × 1000 = 1190 g

one cm = 10 mm

302 / 10 = 30.2 cm

0.018 / 10 =  0.0018 cm

Now we will put the values in formula:

d = m/ l× h× w

l = m / d × h× w

l = 1190 g / 2.7 g/cm³× 30.2 cm × 0.0018 cm

l = 1190 g/ 0.146772 g/cm

l = 8107.81 cm or 81.7081 m

3 0
3 years ago
How do you balance this Chemical Equation? <br>C5H12O + O2 = CO2 + H2O​
ICE Princess25 [194]

Answer:

The chemical equation by putting, a 2 on C₅H₁₂O, 15 on O₂, 10 on CO₂ , and 12 on H₂O in the equation;

2C₅H₁₂O + 15O₂ → 10CO₂ + 12H₂O​

Explanation:

  • Chemical equations are balanced by putting coefficients on the reactants and products to ensure the total number of atoms on the left side equal to those on the right side.
  • Balancing chemical equations is done to make chemical equations obey the law of conservation of mass.
  • According to the law of conservation of mass, the mass of the reactants should always be equal to the mass of products.
  • This is done by balancing chemical equations to ensure the total number of atoms on the left side is equal to that on the right side.
  • Therefore, the balanced equation is;

          2C₅H₁₂O + 15O₂ → 10CO₂ + 12H₂O​

3 0
3 years ago
15.50 g of NH4Cl reacts with an excess of AgNO3. In the reaction 35.50 g AgCl is produced. what is the theoretical yield of AgCl
Readme [11.4K]

Answer:

The answer to your question is 41.6 g of AgCl

Explanation:

Data

mass of NH₄Cl = 15.5 g

mass of AgNO₃ = excess

mass of AgCl = 35.5 g

theoretical yield = ?

Process

1.- Write the balanced chemical reaction.

              NH₄Cl  +  AgNO₃   ⇒   AgCl  +  NH₄NO₃

2.- Calculate the molar mass of NH₄Cl and AgCl

NH₄Cl = 14 + 4 + 35.5 = 53.5 g

AgCl = 108 + 35.5 = 143.5 g

3.- Calculate the theoretical yield

                 53.5 g of NH₄Cl -------------------- 143.5 g of AgCl

                  15.5 g of NH₄Cl  -------------------    x

                         x = (15.5 x 143.5) / 53.5

                         x = 2224.25 / 53.5

                         x = 41.6 g of AgCl

8 0
3 years ago
A lead–tin alloy of composition 30 wt% Sn–70 wt% Pb is slowly heated from a temperature of 150°C (300°F).(a) At what temperature
Novay_Z [31]

Answer:

a) 231.9 °C

b) 100% Sn

c) 327.5 °C

d) 100% Pb

Explanation:

This is a mixture of two solids with different fusion point:

Tf_{Pb}=327.5 C

Tf_{Sn}=231.9 C

<u>Given that Sn has a lower fusion temperature it will start to melt first at that temperature. </u>

So the first liquid phase forms at 231.9 °C and because Pb starts melting at a higher temperature, that phase's composition will be 100% Sn.

The mixture will be completely melted when you are a the higher melting temperature of all components (in this case Pb), so it will all in liquid phase at 327.5 °C.

At that temperature all Sn was already in liquid state and, therefore, the last solid's composition will be 100% Pb.

3 0
3 years ago
Value 1: 45.58g
Rama09 [41]

Answer:

<h2>Percentage error is a measurement of the discrepancy between an observed and a true, or accepted value .</h2>

Explanation:

<h3 />
7 0
3 years ago
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