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Makovka662 [10]
3 years ago
10

Based on the chemical bonds present in this molecule, we would classify it as a(n)

Chemistry
2 answers:
MrMuchimi3 years ago
8 0

Answer is C – Unsaturated fat.

Fats are large molecules basically made from a combination of glycerol and three chains of fatty acids. Usually fats consist of C, H and O. According to the C – C bond, there are two types of fats as saturated fats and unsaturated fats. Saturated fats have only C – C single bonds and all C atoms are sp³ hybridized atoms. But in unsaturated fats other than C – C single bonds there are C – C double bonds. Hence, both sp³ and sp² hybridized C atoms can be seen.


Blizzard [7]3 years ago
4 0
The answer is C. Unsaturated Fat<span />
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Draw the structure corresponding to the common name α−chloro−β−methylbutyric acid
uysha [10]

Structure of a-chloro-b-methylbutyric acid (2-chloro-3-methylbutyric acid is attached below.


The structure was drawn using following information.


1) First, the parent chain was identified. The parent chain is containing four carbon atoms, also, this chain belongs to carboxylic acid as the compound name ends with Butyric acid i.e. butyr (Butane) -ic acid (carboxylic acid).


2) Secondly, the positions of substituents were assigned by using the rule which sates that the numbering in carboxylic acid must satrt from the carbonyl carbon. Therefore, the carbon which is attached to carbonyl carbon is named as alpha (2nd position) and carbon next to alpha carbon is named as beta carbon (3rd position). Hence, we add chlorine atom on 2nd carbon next to carbonyl group and methyl group at 3rd carbon with respect to carbonyl carbon.

6 0
4 years ago
Read 2 more answers
A 1.04L sample of gas of 759 mm Hg pressure is expanded
Marta_Voda [28]

Answer:

P2 = 352 mm Hg (rounded to three significant figures)

Explanation:

PV = nRT

where P is the pressure,

V is the volume,

n is the moles of gas,

R is the gas constant,

and T is the temperature.

We must relate this equation to a sample of gas at two different volumes however. Looking at the equation, we can relate the change in volume by:

P1V1 = P2V2

where P1 is the initial pressure,

V1 is the initial volume,

P2 is the final pressure,

and V2 is the final volume.

Looking at this relationship, pressure and volume have an indirect relationship; when one goes up, the other goes down. In that case, we can use this equation to solve for the new pressure.

P1V1 = P2V2

(759 mm Hg)(1.04 L) = P2(2.24 L)

P2 = 352 mm Hg (rounded to three significant figures)

8 0
3 years ago
What is the wavelength of a wave having a frequency of 2500 Hz
Lemur [1.5K]
We will assume that the wave is moving in free space, thus, the velocity of the wave would be equal to the speed of light = 3 * 10^8 meters/sec

The velocity of the wave can be calculated using the following rule:
velocity = frequency * wavelength where:
velocity = 3 * 10^8 m/sec
frequency = 2500 Hz
wavelength is the unknown that we want to calculate.

Substitute with the givens in the above equation to get the wavelength as follows:
3 * 10^8 = 2500*wavelength
wavelength = 120 * 10^3 meters
5 0
3 years ago
Read 2 more answers
How many outer rings does iodine have
Daniel [21]
53 if your talking about electrons. 74 if your talking about neutrons. energy levels=5 Hope this helps☺️
3 0
3 years ago
A sample of a gas in a rigid container has an initial pressure of 1.049 kPa and an initial temperature of 7.39 K. The temperatur
Doss [256]

Answer:- 4.36 kPa

Solution:- At constant volume, the pressure of the gas is directly proportional to the kelvin temperature.

\frac{P_1}{T_1}=\frac{P_2}{T_2}

Where the subscripts 1 and 2 are representing initial and final quantities.

From given data:

P_1 = 1.049 kPa

P_2 = ?

T_1 = 7.39 K

T_2 = 30.70 K

For final pressure, the equation could also be rearranged as:

P_2=\frac{P_1T_2}{T_1}

Let's plug in the values in it:

P_2=\frac{1.049kPa(30.70K)}{7.39K}

P_2 = 4.36 kPa

So, the new pressure of the gas is 4.36 kPa.

5 0
4 years ago
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