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Ann [662]
3 years ago
6

Write the balanced chemical equations for the decomposition of solid calcium hydroxide into solid calcium (ii) oxide (lime) and

water vapor. express your answer as a balanced chemical equation. identify all of the phases in your answer.
Chemistry
1 answer:
Lesechka [4]3 years ago
3 0

Calcium oxide (CaO) or lime in solid form can be prepared from the decomposition of calcium hydroxide {Ca(OH)_{2} in to lime (CaO) and water (H_{2}O at high temperature. The reaction is an endothermic reaction. That is heat is absorbed in this reaction process. One mole of calcium hydroxide decomposed into one mole of calcium oxide and one mole of water. The balanced reaction can be shown as-CaCO_{3} (solid) → CaO (solid) + H_{2}O (liquid). The heat of the reaction is (+) 63.7 kJ/mole of CaO.

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Compared to a 0.1 M aqueous solution of NaCl, a 0.8 M aqueous solution of NaCl has a
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The correct answer is option 2. A 0.8 M aqueous solution of NaCl has a higher boiling point and a lower freezing point than a 0.1 M aqueous solution of NaCl. This is explained by the colligative properties of solutions. For the two properties mentioned, the equation for the calculation of the depression and the elevation is expressed as: ΔT = -Km and <span>ΔT = Km, respectively. As we can see, concentration and the change in the property has a direct relationship.</span>
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3 years ago
Predict the chemical formula for the ionic compound formed by NH4+ and POsub4exponent3-
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Formula 1!!!!!!!!!!!!!!!!!!!!!!!!!!
4 0
3 years ago
How many sigma bonds does NBr3 have?
Kisachek [45]

Answer:

It has 3 sigma bonds

Explanation:

A sigma bond is a covalent interaction between two atoms, these bonds are the strongest type of covalent bonds and they are formed by the overlap of atomic orbitals.

The nitrogen is bond to the bromine atoms through sigma bonds, which means that exist 3 sigma bonds in the molecule.

this molecule has a trigonal pyramid geometry due to the free pair of nitrogen electrons.

5 0
3 years ago
Determine whether each description applies to electrophilic aromatic substitution or nucleophilic aromatic substitution.
Alborosie

Answer:

a. electrophilic aromatic substitution

b. nucleophilic aromatic substitution

c. nucleophilic aromatic substitution

d. electrophilic aromatic substitution

e. nucleophilic aromatic substitution

f. electrophilic aromatic substitution

Explanation:

Electrophilic aromatic substitution is a type of chemical reaction where a hydrogen atom or a functional group that is attached to the aromatic ring is replaced by an electrophile. Electrophilic aromatic substitutions can be classified into five classes: 1-Halogenation: is the replacement of one or more hydrogen (H) atoms in an organic compound by a halogen such as, for example, bromine (bromination), chlorine (chlorination), etc; 2- Nitration: the replacement of H with a nitrate group (NO2); 3-Sulfonation: the replacement of H with a bisulfite (SO3H); 4-Friedel-CraftsAlkylation: the replacement of H with an alkyl group (R), and 5-Friedel-Crafts Acylation: the replacement of H with an acyl group (RCO). For example, the Benzene undergoes electrophilic substitution to produce a wide range of chemical compounds (chlorobenzene, nitrobenzene, benzene sulfonic acid, etc).

A nucleophilic aromatic substitution is a type of chemical reaction where an electron-rich nucleophile displaces a leaving group (for example, a halide on the aromatic ring). There are six types of nucleophilic substitution mechanisms: 1-the SNAr (addition-elimination) mechanism, whose name is due to the Hughes-Ingold symbol ''SN' and a unimolecular mechanism; 2-the SN1 reaction that produces diazonium salts 3-the benzyne mechanism that produce highly reactive species (including benzyne) derived from the aromatic ring by the replacement of two substituents; 4-the free radical SRN1 mechanism where a substituent on the aromatic ring is displaced by a nucleophile with the formation of intermediary free radical species; 5-the ANRORC (Addition of the Nucleophile, Ring Opening, and Ring Closure) mechanism, involved in reactions of metal amide nucleophiles and substituted pyrimidines; and 6-the Vicarious nucleophilic substitution, where a nucleophile displaces an H atom on the aromatic ring but without leaving groups (such as, for example, halogen substituents).

3 0
3 years ago
If you measured out 100.0g of water, how many molecules of water would you have drank?
12345 [234]
<h3>Answer:</h3>

3.342 x 10^24 molecules of water

<h3>Explanation:</h3>

Given;

Mass of water = 100.0 g

Required to determine the number of molecules in 100.0 g of water

Using Avogadro's constant

1 mole of a compound contains 6.022 × 10^22  molecules

Thus;

1 mole of H₂O contains 6.022 × 10^23 molecules

But;

1 mole = 18.02 g/mol

Therefore;

18.02 g of water contains 6.022 × 10^23 molecules

100.0 g of water will have;

= (100. 0 g ×6.022 × 10^23 molecules) ÷ 18.02

= 3.342 x 10^24 molecules

8 0
3 years ago
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