Answer:
The chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.
Explanation:
The chemical potential of 2-propanol in solution relative to that of pure 2-propanol can be calculated using the following equation:
<u>Where:</u>
<em>μ (l): is the chemical potential of 2-propanol in solution </em>
<em>μ° (l): is the chemical potential of pure 2-propanol </em>
<em>R: is the gas constant = 8.314 J K⁻¹ mol⁻¹ </em>
<em>T: is the temperature = 82.3 °C = 355.3 K </em>
<em>x: is the mole fraction of 2-propanol = 0.41 </em>
Therefore, the chemical potential of 2-propanol in solution relative to that of pure 2-propanol is lower by 2.63x10⁻³.
I hope it helps you!
Answer:
Whether something is a molecule or not depends on the type of bond that is formed when its atoms join together. In general, electrons can be shared between atoms (a molecular bond) or electrons can be completely removed from one atom and given to another (an ionic bond). Molecules have molecular bonds.
Moles of CO2 = number of molecules / 6.02x10^23. = 3x10^23/6.02x10^23 = 0.5moles. Therefore, mass of CO2 = moles x molecular mass of CO2= 0.5x44 = 22gm.
The reason for adding a limited amount and then an excess amount is that initially a metal hydroxide may form which becomes soluble when more base is added and the metal complex forms.
In qualitative analysis is a common to add the base in drops and then in excess. When added in drops, the metal hydroxide is formed. This metal hydroxide is often insoluble.
After this metal hydroxide is formed, the base could be added in excess such that the metal hydroxide dissolves in the excess base by forming a complex.
For instance;
CuCl2(aq) + 2NaOH(aq) -------> Cu(OH)2(s) + 2NaCl(aq)
Cu(OH)2(s) + 2OH^-(aq) -------> [Cu(OH)4]^2+(aq)
Learn more: brainly.com/question/1527403
<h3>Answer:</h3>
3.7 Moles of Nitrogen
<h3>
Explanation:</h3>
On observing the chemical formula C₈H₁₁NO₂ (might be formula of Dopamine) it is found that one mole of this compound contains;
8 Moles of Carbon
11 Moles of hydrogen
1 Mole of Nitrogen and
2 Moles of Oxygen respectively.
<u>Calculate Number of Moles of Nitrogen:</u>
As,
1 Mole of C₈H₁₁NO₂ contains = 1 Mole of Nitrogen
So,
3.7 Moles of C₈H₁₁NO₂ will contain = X Moles of Nitrogen
Solving for X,
X = (3.7 Moles × 1 Mole) ÷ 1 Mole
X = 3.7 Moles of Nitrogen
