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Alenkinab [10]
3 years ago
8

A flower shop sells tulips and roses. The price of each tulip is the same and the price of each roses the same. One customer bou

ght seven tulips and nine roses for $25.90. Another customer bought for two lips and eight roses for $19.80 how much will it cost a customer to buy five tulips and six roses
Mathematics
1 answer:
Talja [164]3 years ago
7 0

Answer: it cost a customer $7.25 to buy five tulips and $10.5 to buy six roses.

Step-by-step explanation:

Let x represent the cost of 1 tulip.

Let y represent the cost of 1 rose.

The price of each tulip is the same and the price of each roses the same. One customer bought seven tulips and nine roses for $25.90. This means that

7x + 9y = 25.9 - - - - - - - - - - - - - - 1

Another customer bought for four tulips and eight roses for $19.80. This means that

4x + 8y = 19.8- - - - - - - - - - - - - - - 2

Multiplying equation 1 by 4 and equation 2 by 7, it becomes

28x + 36y = 103.6

28x + 56y = 138.6

Subtracting, it becomes

- 20y = - 35

y = - 35/ - 20

y = 1.75

Substituting y = 1.75 into equation 2, it becomes

4x + 8 × 1.75 = 19.8

4x + 14 = 19.8

4x = 19.8 - 14 = 5.8

x = 5.8/4

x = 1.45

The cost of 5 tulips would be

1.45 × 5 = $7.25

The cost of 6 roses would be

1.75 × 6 = $10.5

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Answer:

1) Zero based on (-16·t - 2) is t = -1/8 second

2) Zero based on (t - 1) is t = 1 second

Step-by-step explanation:

The given functions representing the height of the beach ball the child throws as a function of time are;

y = (-16·t - 2)·(t - 1) and y = -16·t² + 14·t + 2

We note that (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

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The zeros of a function are the values of the variables, 'x', of the function that makes the value of the function, f(x), equal to zero

In the function of the question, we have;

y = (-16·t - 2)·(t - 1) = -16·t² + 14·t + 2

The above equation can be written as follows;

y = (-16·t - 2) × (t - 1)

Therefore, 'y' equals zero when either (-16·t - 2) = 0 or (t - 1) = 0

1) The zero based on (-16·t - 2) = 0, is given as follows;

(-16·t - 2) = 0

∴ t = 2/(-16) = -1/8

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