Ok so assume that if you have
xy=0 then x and y=0
-1/4(x^2-4x+3)>0
multiply both sides by -4 to clear fraction (-4/-4=1)
flip sign
x^2-4x+3<0
factor
(x-3)(x-1)<0
we know that (+) times (-)=(-) and
(-) times (-)=(+) so we don't want them to be both negative, we want different sign
we cannnot have 3 since it would be (0)(2)<0 which is false
we cannot have 1 either since (-2)(0)<0 is also false
lets see if the solution is in betwen 3 and 1 or outside of 3 and 1
ltry 2
2^3-4(2)+3<0
8-8+3<0
3<0
false
therefor it is outside ie
x>3 and x<1
Is it 79 sets of ten or 79 tenths
Answer:
Area =
b1 + b2
×h
2
=
2 + 6
× 5
2
=
20 centimeters2
Step-by-step explanation:
Answer:
Sometimes
Step-by-step explanation:
I’ll give you an example so you can understand:
Let’s say x is 4. So plug 4 into the problem:
|4|=4 → This is a very true statement, where the absolute value of 4 is equal to 4.
Now, let’s say x is -7. So plug -7 into the problem:
|-7|=-7 → This is a false statement because it’s saying that the absolute value of -7 is -7 which is very untrue.
So |x|=x only works for positive numbers, but not negative numbers. Therefore, |x|=x is the absolute value of x <u>sometimes.</u>
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Hope this helps and answers your question! :)
Answer:
3
Step-by-step explanation:
I searched it up on the web
