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Ganezh [65]
3 years ago
15

CAN SOMEONE PLEASE HELP!!!! determine the value of x. i’ll give you points if you answer!

Mathematics
1 answer:
salantis [7]3 years ago
7 0

Answer:

2.4

Step-by-step explanation:

Look up 30-60-90 right triangle and use that formula. Since the angle in the middle is 90 degrees, it should work. The side of x would be double of the given side 1.2... this is what I would do

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How many solutions are there in the given equation?<br> y = 2x² + 6x + 4
tigry1 [53]

Step-by-step explanation:

Use the quadratic formula

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−

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x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

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2x^{2}+6x+4=0

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a={\color{#c92786}{2}}

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c={\color{#129eaf}{4}}

c=4

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x=\frac{-{\color{#e8710a}{6}} \pm \sqrt{{\color{#e8710a}{6}}^{2}-4 \cdot {\color{#c92786}{2}} \cdot {\color{#129eaf}{4}}}}{2 \cdot {\color{#c92786}{2}}}

x=2⋅2−6±62−4⋅2⋅4

brainliest and follow and thanks

8 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST IF CORRECT!!
Montano1993 [528]

Answer:

the second one  +1.5 m/s

Step-by-step explanation:

to find the velocity you need to find the slope of the two points then just put it into the time (s) and position (m) terms which equals +1.5 m/s

7 0
3 years ago
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If f(x)= x+7 and g(x)= 1/x-13
Natasha2012 [34]
1. x = y - 7
2. g = x12
4 0
3 years ago
Please someone help me to prove this. ​
dem82 [27]
<h3><u>Answer</u> :</h3>

We know that,

\dag\bf\:sin^2A=\dfrac{1-cos2A}{2}

\dag\bf\:sin2A=2sinA\:cosA

<u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u>

<u>Now, Let's solve</u> !

\leadsto\:\bf\dfrac{sin^2A-sin^2B}{sinA\:cosA-sinB\:cosB}

\leadsto\:\sf\dfrac{\frac{1-cos2A}{2}-\frac{1-cos2B}{2}}{\frac{2sinA\:cosA}{2}-\frac{2sinB\:cosB}{2}}

\leadsto\:\sf\dfrac{1-cos2A-1+cos2B}{sin2A-sin2B}

\leadsto\:\sf\dfrac{2sin\frac{2A+2B}{2}\:sin\frac{2A-2B}{2}}{2sin\frac{2A-2B}{2}\:cos\frac{2A+2B}{2}}

\leadsto\:\sf\dfrac{sin(A+B)}{cos(A+B)}

\leadsto\:\bf{tan(A+B)}

5 0
3 years ago
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PLEASE HELP ASAP! BRAINLIEST TO BEST/RIGHT ANSWER
Butoxors [25]
I won't bore you with the details, but according to my math the answer should be C. 1/2. 
5 0
3 years ago
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