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Oksi-84 [34.3K]
2 years ago
8

If the lengths of the legs of a right angle are 5 and 7, what is the length of the hypotenuse?

Mathematics
1 answer:
Natalija [7]2 years ago
6 0

Answer:

7^2 + 5^2 = 49 + 25 = 74

hypotenuse = square root of 74

Answer is B

Step-by-step explanation:

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Y=x^2+5x-8 to factored form
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2^5 + 4^3 – 6x + 3

Step-by-step explanation:

Order the numbers by decreasing exponents. Start with the 2^5, since it has an exponent of 5. Next is the 4^3 since it has an exponent of 3. After that is -6x since it has an exponent of 1. 3 is last because it has an exponent of 1 and it has no variables attached.

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3 years ago
Read 2 more answers
Help please rn help
aksik [14]

Area of the large semicircle

= \pi{r}^{2}  \div 2

=  \frac{22}{7}  \times 12 {}^{2}  \times  \frac{1}{2}

=  \frac{11}{7}  \times12 \times 12

=  \frac{11}{7}  \times 144

= 226.28

Area of the small semicircle

= \pi  {r}^{2}  \div 2

=  \frac{22}{7}  \times 6 {}^{2}  \times  \frac{1}{2}

=  \frac{11}{7}  \times 6 \times 6

=  \frac{11}{7}  \times 36

= 56.57

Area of the figure

= 226.28 - 56.57

= 169.71 {cm}^{2}

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Step-by-step explanation:

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