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3 years ago

The graph of y = lxl

Mathematics

1 answer:

Gelneren [198K]3 years ago

5 0

Answer:

y = |x - 5| + 4

Step-by-step explanation:

Because the graph is shifted up 4 units, that means the equation of the graph is:

y = |x| + 4

Because you are moving it 5 units to the right, the new equation is:

y = |x - 5| + 4

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3 years ago

A glacier in Alaska moves about 29.9 meters a day. About how much farther will mobe in 1,000 days than it will move in 100 days

Reptile [31]

Answer:

26,910 meters

Step-by-step explanation:

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3 years ago

Solve the inequalities from parts A and D for the variables b and n, respectively.

Greeley [361]

Answer:

Part A: b < 28

Part D: n < 56

Step-by-step explanation:

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part d: this is already solved but can be shown in multiple forms.

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Interval Notation: ( -∞ , 56)

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2 years ago

Prove or disprove that the point (√5, 12) is on the circle centered at the origin and containing the point (-13, 0). Show your w

pav-90 [236]

Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.

<h3>What is the equation of a circle?</h3>

The equation of a circle of center $(x_0, y_0)$ and radius r is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

In this problem, the circle is centered at the origin, hence $(x_0, y_0) = (0,0)$ .

The circle contains the point (-13,0), hence the radius is found as follows:

$x^2 + y^2 = r^2$

$(-13)^2 + 0^2 = t^2$

$r^2 = 169$

Hence the equation is:

$x^2 + y^2 = 169$

Then, we test if point (√5, 12) is on the circle:

$x^2 + y^2 = 169$

$(\sqrt{5})^2 + 12^2 = 169$

25 + 144 = 169

Which is an identity, hence point (√5, 12) is on the circle.

More can be learned about the equation of a circle at brainly.com/question/24307696

#SPJ1

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3 years ago