What is 5y-4(-4-7y) using Distributive property
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Answer:
You can decide to <u>reject</u> the Null Hypothesis at p < 0.05.
Step-by-step explanation:
In this case, the relationship between the history of early childhood trauma and weight in adulthood are being studied.
The categories of childhood trauma are:
Trauma and No trauma.
So, number of rows is, <em>r</em> = 2.
The categories of weight in adulthood are:
Low to normal, Overweight, and Obese
So, number of columns is, <em>c</em> = 3.
The distribution of the statistic is chi-square with (<em>r </em>- 1)(<em>c </em>- 1) degrees of freedom, where <em>r</em> represents the number of rows in the two-way table and <em>c</em> represents the number of columns.
Compute the degrees of freedom as follows:
It is provided that the calculated value of Chi-square test statistic is 18.26.
Compute the <em>p</em>-value of the test as follows:
Decision rule:
The null hypothesis will be rejected if the <em>p</em>-value of the test is less than the significance level.
The significance level is, <em>α</em> = 0.05.
<em>p</em>-value = 0.00011 < <em>α</em> = 0.05.
The null hypothesis will be rejected at 5% level of significance.
Thus, the complete statement is:
"You can decide to <u>reject</u> the Null Hypothesis at p < 0.05."