Answer:
The ratio of the radius of the smaller watch face to the radius of the larger watch face is 4:5.
Step-by-step explanation:
Let the Area of smaller watch face be 
Also Let the Area of Larger watch face be 
Also Let the radius of smaller watch face be 
Also Let the radius of Larger watch face be 
Now given:

We need to find the ratio of the radius of the smaller watch face to the radius of the larger watch face.
Solution:
Since the watch face is in circular form.
Then we can say that;
Area of the circle is equal 'π' times square of the radius 'r'.
framing in equation form we get;


So we get;

Substituting the value we get;

Now 'π' from numerator and denominator gets cancelled.

Now Taking square roots on both side we get;

Hence the ratio of the radius of the smaller watch face to the radius of the larger watch face is 4:5.
Answer:
You can look down
Step-by-step explanation:
Okay so you can put this has a mixed faction.
so it is 46/3. and then you can simplify it and you get the same answer. 14 2/3 but you still cant simplify it because all numbers are un-even. like you cant simplify.
The given compound inequality is

First we solve the first inequality,

Now we solve the second inequality

So we have

So the required solution is
![( - \infty,-5] \ or \ (0, \infty)](https://tex.z-dn.net/?f=%20%28%20-%20%5Cinfty%2C-5%5D%20%5C%20or%20%5C%20%280%2C%20%5Cinfty%29%20)
Correct option is A .
Answer:
Y=9x-21
Step-by-step explanation:
The solution is x>18.
The problem tells us that 3 less than a number: x-3
is more than 15. >15
So the inequality is x-3>15. When we isolate x to simply the inequality, we add 3 to both sides, to get x>18.
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