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Dominik [7]
4 years ago
5

Kenya exchanges $150 for British pounds(£). Suppose the conversion rate is £1 = $1.60. How many pounds should she receive?

Mathematics
2 answers:
FromTheMoon [43]4 years ago
7 0

If $1.60 is 1 pound,  You Should divide the $ amount by 1.60 to find the number of pounds.

So pretty much it'll look like this ( Below)

150/1.6

= 93.75

Misha Larkins [42]4 years ago
6 0
If $1.60 is 1 pound, divide the $ amount by 1.60 to find the number of pounds. 150/1.6 = 93.75
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ser-zykov [4K]

Answer: 4/5

Step-by-step explanation:

--------------------------------No of vehicles involved

Did alcohol play a role - - 1 - - - - - 2 - - - - - 3

Yes---------------------------- 60 - - - - 110 - - - 30=200

No - - - - - - - - - - - - - - - - 40 - -- - 215 - - - 45 =300

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What proportion of accidents involved more than one vehicle;

Total accident = (100 + 325 + 75) = 500

Number of accidents involving more than one vehicle = (accident involving 2 vehicles + accident involving 3 vehicles)

(325 + 75) = 400

Therefore, proportion of accidents involved more than one vehicle = (Accident involving more than one vehicle / total accidents)

= (400/ 500) = 4/5

6 0
3 years ago
How many mLs are in 1300mG
Thepotemich [5.8K]

Answer:

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7 0
3 years ago
Read 2 more answers
a number is multiplied by 8 and that product is added to 2. The sum is equal to the product of 2 and 25 . Find the number
pickupchik [31]

Answer:

6

Step-by-step explanation:

So we have a number (let's call it x) and it was multiplied by 8 and added by 2. Therefore:

8x+2

And we are told that the sum is equal to the product of 2 and 25 (or 50). Thus:

8x+2=50

To find the number, we just need to find x. Thus, subtract 2 from both sides:

8x=48

Divide both sides by 8:

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And we're done!

So, our original number was 6.

8 0
3 years ago
Find the inverse of the function. f(x) = 6x3 - 8
Papessa [141]
\bf f(x)=y=6x^3-8\qquad inverse\implies 
\begin{array}{lll}
x=&6y^3-8\\
&\uparrow\\
&\textit{switched variables} 
\end{array}
\\\\\\
x+8=6y^3\implies \cfrac{x+8}{6}=y^3\impliedby taking\ \sqrt[3]{\qquad }
\\\\\\
\sqrt[3]{\cfrac{x+8}{6}}=\sqrt[3]{y^3}\implies \sqrt[3]{\cfrac{x+8}{6}}=y\impliedby f^{-1}(x)
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3 years ago
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