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sveta [45]
4 years ago
8

What is the solution to the equation x + 11 = 57? (Input a whole number only.) Numerical Answers Expected! Answer for Blank 1:

Mathematics
1 answer:
Ymorist [56]4 years ago
6 0
X + 11 = 57 
    - 11   - 11 
x = 46
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The angles and sides in each triangle and classify it in 2 ways
nikdorinn [45]
You have to measure the angles and side on your own because you have to use a protractor/ruler. 
But for classification:
1. acute triangle and 3 acute angles
2. right triangle and 1 right angle
3. isosceles triangle and 2 equal sides
4. equilateral triangle and 3 equal sides
3 0
3 years ago
Find general solutions of the differential equation. Primes denote derivatives with respect to x.
zepelin [54]

Answer:

\mathbf{3x^2y^3+2xy^4=C}

Step-by-step explanation:

From the differential equation given:

6xy^3 +2y ^4 +(9x^2y^2+8xy^3) y' = 0

The equation above can be re-written as:

6xy^3 +2y^4 +(9x^2y^2+8xy^3)\dfrac{dy}{dx}=0

(6xy^3 +2y^4)dx +(9x^2y^2+8xy^3)dy=0

Let assume that if function M(x,y) and N(x,y) are continuous and have continuous first-order partial derivatives.

Then;

M(x,y) dx + N (x,y)dy = 0; this is exact in R if and only if:

\dfrac{{\partial M }}{{\partial y }}= \dfrac{\partial N}{\partial  x}}} \ \ \text{at each point of R}

relating with equation M(x,y)dx + N(x,y) dy = 0

Then;

M(x,y) = 6xy^3 +2y^4\  and \ N(x,y) = 9x^2 y^2 +8xy^3

So;

\dfrac{\partial M}{\partial y }= 18xy^3 +8y^3

       \dfrac{\partial N}{\partial y }

Let's Integrate \dfrac{\partial F}{\partial x}= M(x,y) with respect to x

Then;

F(x,y) = \int (6xy^3 +2y^4) \ dx

F(x,y) = 3x^2 y^3 +2xy^4 +g(y)

Now, we will have to differentiate the above equation with respect to y and set \dfrac{\partial F}{\partial x}= N(x,y); we have:

\dfrac{\partial F}{\partial y} = \dfrac{\partial}{\partial y } (3x^2y^3+2xy^4+g(y)) \\ \\ = 9x^2y^2 +8xy^3 +g'(y) \\ \\ 9x^2y^2 +8xy^3 +g'(y) =9x^2y^2 +8xy^3 \\ \\ g'(y) = 0  \\ \\ g(y) = C_1

Hence, F(x,y) = 3x^2y^3 +2xy^4 +g(y)  \\ \\ F(x,y) = 3x^2y^3 + 2xy^4 +C_1

Finally; the general solution to the equation is:

\mathbf{3x^2y^3+2xy^4=C}

5 0
3 years ago
i need help with number 7. its solving systems of equations by substitution. please show work!!! i need help
SIZIF [17.4K]
#7:
<span>Subtract </span>y<span> from both sides:
</span>-4x=6-y

Divide both sides by -4:

Answer:
x= -6-y/4


#7 part 2:

Add <span>y</span><span> to both sides:
</span>-5x=21+y

Divide both sides by -5:

Answer: x=-21+y/5

hope i helped!



7 0
3 years ago
Simplify expression 2/3[3f+12]+f
neonofarm [45]

Answer:

= 3f + 8

Step-by-step explanation:

Given that:

= 2/3[3f+12]+f

By simplifying:

2/3 will be multiplied inside the bracket as follows:

= 2/3*3f + 2/3*12 + f

By cancelling the terms with each other we get:

= 2f + 24/3 + f

By simplifying the fraction we get:

= 2f + 8 + f

Adding like terms

= 3f + 8

This is the simplified expression.

i hope it will help you!

4 0
3 years ago
Please please help me please help help me and show your steps please
Serga [27]

Answer:

please help help help help help

Step-by-step explanation:

lol

7 0
3 years ago
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