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Pepsi [2]
4 years ago
10

Which is the correct answer?? Can you help please?

Physics
1 answer:
Vera_Pavlovna [14]4 years ago
6 0
A.) it considered societal needs


I believe so
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faltersainse [42]
The name carbohydrate means "watered carbon" or carbon with attached water molecules. Many carbohydrates have empirical formuli which would imply about equal numbers of carbon and water molecules. For example, the glucose formula C6H12O6 suggests six carbon atoms and six water molecules.
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What is the speed of a 500 kg elevator that has 4000 J of energy ?
malfutka [58]
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8 0
3 years ago
A 2kg mass is initially at rest on a frictionless surface. A 45N force acts at an angle of 300
raketka [301]

Answer:

a) The work done by the force is 136.400 joules.

b) The speed of the mass at the end of the 3.5 meters is approximately 11.679 meters per second.

Explanation:

The correct statement is shown below:

<em>A 2-kg mass is initially at reat on a frictionless surface. A 45 N force acts at an angle of 30º to the horizontal for a distance of 3.5 meters:</em>

<em>a)</em><em> Find the work done by the force.</em>

<em>b)</em><em> Find the speed of the mass at the end of the 3.5 meters.</em>

a) Given that a external constant force is acting on the mass on a frictionless surface, the work done by the force (W_{F}), measured in joules, is:

W_{F} = F\cdot \Delta s \cdot \cos \theta (1)

Where:

F - External constant force exerted on the mass, measured in newtons.

\Delta s - Horizontal travelled distance, measured in meters.

\theta - Direction of the external force regarding the horizontal, measured in sexagesimal degrees.

If we know that F = 45\,N, \Delta s = 3.5\,m and \theta = 30^{\circ}, then the work done by the force is:

W_{F} = (45\,N)\cdot (3.5\,m)\cdot \cos 30^{\circ}

W_{F} = 136.400\,J

The work done by the force is 136.400 joules.

b) The final speed of the mass at the end ot the 3.5 meter is calculated by means of the Work-Energy Theorem, which means that the work done on the mass is transformed into a translational kinetic energy. That is:

W_{F} = \frac{1}{2}\cdot m \cdot (v_{2}^{2}-v_{1}^{2}) (2)

Where:

m - Mass, measured in kilograms.

v_{1}, v_{2} - Initial and final speeds of the mass, measured in meters per second.

If we know that W_{F} = 136.400\,J, m = 2\,kg and v_{1} = 0\,\frac{m}{s}, then the final speed of the mass is:

\frac{2\cdot W_{F}}{m} = v_{2}^{2}-v_{1}^{2}

v_{2}^{2} =v_{1}^{2}+\frac{2\cdot W_{F}}{m}

v_{2} =\sqrt{v_{1}^{2}+\frac{2\cdot W_{F}}{m} }

v_{2} =\sqrt{\left(0\,\frac{m}{s} \right)^{2}+\frac{2\cdot (136.400\,J)}{2\,kg} }

v_{2} \approx 11.679\,\frac{m}{s}

The speed of the mass at the end of the 3.5 meters is approximately 11.679 meters per second.

3 0
3 years ago
A ray of light passes from air into carbon disulfide (n = 1.63) at an angle of 28.0 degrees to the normal. what is the refracted
Snezhnost [94]
We can solve the problem by using Snell's law, which states 
n_i \sin \theta_i = n_r \sin \theta_r
where
n_i is the refractive index of the first medium
\theta_i is the angle of incidence
n_r is the refractive index of the second medium
\theta_r is the angle of refraction

In our problem, n_i=1.00 (refractive index of air), \theta_i = 28.0^{\circ} and n_r=1.63 (refractive index of carbon disulfide), therefore we can re-arrange the previous equation to calculate the angle of refraction:
\sin \theta_r =  \frac{n_i}{n_r}  \sin \theta_r =  \frac{1.00}{1.63}  \sin 28.0^{\circ} = 0.288
From which we find
\theta_r = \arcsin (0.288)=16.7^{\circ}
6 0
3 years ago
Need help ASAP
vlada-n [284]

(1) The parallel force on the Jumper is 441.42 N.

(2) The weight of the person is heavier on Earth when compared to Mars by 610 N.

<h3>Parallel force on the Jumper</h3>

The parallel force on the Jumper is determined from the parallel components of the weight of the jumper.

F = W x sinθ

F = (85 x 9.8) x sin32

F = 441.42 N

<h3>Weight of the person on Earth</h3>

W = mg

W = 100 x 9.8

W = 980 N

<h3>Weight of the person on Mars</h3>

W = mg

W = 100 x 3.7

W = 370 N

<h3>Difference between the weights</h3>

= 980 N - 370 N

= 610 N

Thus, the weight of the person is heavier on Earth when compared to Mars by 610 N.

Learn more about weight here: brainly.com/question/2337612

#SPJ1

4 0
2 years ago
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