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Dafna11 [192]
2 years ago
8

a bicycle uniformly from rest at time t the velocity of the bicycle is v at what time will the bicycle have a velocity of 4v​

Physics
1 answer:
sesenic [268]2 years ago
7 0

Here

  • Acceleration and initial velocities are constant.

According to first equation of kinematics.

\\ \sf\longmapsto v=u+at

\\ \sf\longmapsto v=0+at

\\ \sf\longmapsto v=at

\\ \sf\longmapsto v\propto t

  • Time was t at velocity v
  • Time will be 4t at velocity 4v
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Match the following list of key words with their definitions
Korvikt [17]

Question 1 :

1.  VELOCITY

2.  SPEED

3.  NEWTON

4.  MOMENTUM

5.  MASS

Question 2

1.     FORCE

2.    FRICTION

3.    GRAVITY

4.    ELECTROAGNETIC FORCE

5.    ACCELERATION

6 0
2 years ago
f you were trying to build a soundproof room, which of the following materials would you choose in order to absorb the most soun
musickatia [10]
If you don't have the coefficient of absorption, I would say Heavy curtains.

Hope this helps :)
5 0
3 years ago
Write the equation that links current, potential difference, and resistance
mrs_skeptik [129]

You can write the equation in 3 different ways, depending on which quantity you want to be the dependent variable.  Any one of the three forms can be derived from either of the other two with a simple algebra operation.  They're all the same relationship, described by "Ohm's Law".

==> Current = (potential difference) / (resistance)

==> Potential difference = (current) x (resistance)

==> Resistance = (potential difference) / (resistance)

4 0
3 years ago
A train whistle is heard at 300 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and t
givi [52]

To solve this problem we will apply the concepts related to the Doppler effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. Mathematically it can be described as,

f = f_0 (\frac{v_0}{v_0-v})

Here,

f_0 = Frequency of Source

v_s = Speed of sound

f = Frequency heard before slowing down

f' = Frequency heard after slowing down

v  = Speed of the train before slowing down

So if the speed of the train after slowing down will be v/2, we can do a system equation of 2x2 at the two moments, then,

The first equation is,

f = f_0 (\frac{v_0}{v_0-v})

300 = f_0 (\frac{343}{343-v})

(300*343) - 300v = 343f_0

Now the second expression will be,

f' = f_0 (\frac{v_0}{v_0-v/2})

290 = (343)(\frac{v_0}{343-v/2})

290*343-145v = 343f_0

Dividing the two expression we have,

\frac{(300*343) - 300v}{290*343-145v} = 1

Solving for v, we have,

v = 22.12m/s

Therefore the speed of the train before and after slowing down is 22.12m/s

6 0
3 years ago
A hockey player uses her hockey stick to exert a force of 6.81 N on a stationary hockey puck. The hockey puck has a mass of 165
Anna007 [38]

Answer:

41.3 m/s^2 option (e)

Explanation:

force, F = 6.81 N

mass, m = 165 g = 0.165 kg

Let a be the acceleration of the puck.

Use newtons' second law

Force = mass x acceleration

6.81 = 0.165 x a

a = 41.27 m/s^2

a = 41.3 m/s^2

Thus, the acceleration of the puck is 41.3 m/s^2.

5 0
3 years ago
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