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3 years ago

a bicycle uniformly from rest at time t the velocity of the bicycle is v at what time will the bicycle have a velocity of 4v

Physics

1 answer:

sesenic [268]3 years ago

7 0

Here

Acceleration and initial velocities are constant.

According to first equation of kinematics.

$\\ \sf\longmapsto v=u+at$

$\\ \sf\longmapsto v=0+at$

$\\ \sf\longmapsto v=at$

$\\ \sf\longmapsto v\propto t$

Time was t at velocity v
Time will be 4t at velocity 4v

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A block of aluminum with a volume of 10 cm3 is placed in a beaker of water filled to the brim. Water overflows. The same is done

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Answer:

a) Both blocks displace the same amount of water.

Explanation:

Specific gravity (S.G.) is a quantity that tells how much and object is submerged on water and is given by:

$S.G=\frac{\rho_{block}}{\rho_{fluid}}$

with ρ the densities

Density of water is $997 \frac{kg}{m^{3}}$ and density of aluminum is $2712 \frac{kg}{m^{3}}$

So:

$S.G=\frac{2712}{997}=2.72$

A S.G. value bigger than one means the object is totally submerged so the water displaced is equal to the volume of the cube.

For the lead (density = $11340\frac{kg}{m^{3}}$ ) block we're going to calculate specific gravity in this case:

$S.G=\frac{11340}{997}=11.37$

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3 years ago

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Answer:

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How are the functions of the cytoskeleton and the cell wall similar

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3 years ago

Using a refracting telescope, you observe the planet Mars when it is 2.11 × 10 11 m 2.11×1011 m from Earth. The diameter of the

Norma-Jean [14]

Answer:

y = 150 Km

Explanation:

given,

Distance of the planet Mars from earth D = 2.11 × 10¹¹ m

The diameter of the telescope's objective lens d = 0.949 m

The wavelength of light λ = 553 nm

= 553 x 10⁻⁹ m

resolution of the telescope = ?

$y = \dfrac{1.22\lambda\ D}{d}$

$y = \dfrac{1.22\times 553\times 10^{-9}\times 2.11 \times 10^{11}}{0.949}$

y = 150003 m

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3 years ago

Point PP is a distance d1d1 = 4.0 mm above a large sheet of metal that carries a current of 35 AA in the positive xx direction a

zhenek [66]

Answer:

The width of the sheet is $w =0.8046m$

Explanation:

From the question we are told that

The distance of point P above a large sheet of metal is $D = 4.0mm =\frac{4}{1000} = 0.004m$

The current on the large metal sheet is $I =34A$

The distance of the the point P below a long wire $d = 3.0mm = \frac{3}{1000} = 0.003m$

The current on the long wire is $I_w = 0.41A$

The magnetic field at P is $B = 0T$

Generally magnetic field of P long wire is mathematically represented as

$B_w = \frac{\mu_o I_w}{2\pi r}$

Generally magnetic field of P large sheet of meta is mathematically represented as

$B_m = \frac{\mu_o K}{2}$

Where K is the current per unit width

The total magnetic field at P is

$\frac{\mu_o I_w}{2 \pi r} = \frac{\mu_o K}{2}$

Making K the subject of formula

$K = \frac{2 I_w }{2 \pi r }$

Substituting values

$K = \frac{2 * 0.41 }{2 * 3.142 * (0.0030) }$

$K = 43.4967 A/m$

Generally K is mathematically represented as

$K = \frac{I}{w}$

Where w is the width of the large sheet

Therefore the width of the metal sheet $w = \frac{I}{K}$

$= \frac{35}{43.4967}$

$w =0.8046m$

7 0

3 years ago

a bicycle uniformly from rest at time t the velocity of the bicycle is v at what time will the bicycle have a velocity of 4v​

a bicycle uniformly from rest at time t the velocity of the bicycle is v at what time will the bicycle have a velocity of 4v