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abruzzese [7]
4 years ago
7

Consider a spherical volume of space that is large enough to be considered homogeneous. Also consider a particle on the surface

of this volume that is moving away from the center with the Hubble flow. Assuming that the pressure within the volume is negligible, the universe will re-collapse if the particle's Hubble speed is: A. Greater than its escape speed from the mass within the volume B. The same as its escape speed from the mass within the volume C. Less than its escape speed from the mass within the volume
Physics
1 answer:
LenKa [72]4 years ago
3 0

Answer:

Option A applies.

A.  Greater than its escape speed from the mass within the volume

Explanation:

Here it is mentioned that the spherical volume is large enough for the space to be considered as homogeneous. Also, the pressure within the volume is negligible, so that will not result into the re collapse of the Universe. Now as per our knowing, Hubble's Law relates the average speed of the particle to the distance R between the Earth and the particle. So, if the particle's speed is greater than it's escape speed from the mass within the volume, then the Universe is bound to re collapse back again. Option A applies.

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A cannon ball is launched off a 100 m cliff horizontally with an initial horizontal velocity (Vx) of 50 m/s.
denis-greek [22]

We have the equation of motion s = ut+\frac{1}{2} at^2 , where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.

Here displacement = 100 m, Initial velocity = 0 m/s, acceleration = 9.81 m/s^2

Substituting

100 = 0*t+\frac{1}{2} *9.8*t^2\\ \\ 100 = 4.9t^2\\ \\ t = 4.52 seconds

A cannon ball is launched off a 100 m cliff horizontally with an initial horizontal velocity (Vx) of 50 m/s will take 4.52 seconds to reach the ground.


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3 years ago
Il record del mondo sulla maratona appartiene al grande Eliud Kipchoge con il tempo di 2h 01' 39"
SVETLANKA909090 [29]

Answer: 7260,39

Explanation:

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3 years ago
I need help with number 2 pls it’s a quiz grade
Eduardwww [97]
2 is correct hope you get it right
8 0
3 years ago
A 60.00-cm guitar string under a tension of 50.000 N has a mass per unit length of 0.100 00 g/cm chegg
Evgen [1.6K]

Fundamental frequency,

f=v2l=T/μ−−−−√2l

=(50)/0.1×10−3/10−22×0.6−−−−−−−−−−−−−−−−−−−√

=58.96Hz

Let, n th harmonic is the hightest frequency, then

(58.93)n = 20000

∴N=339.38

Hence, 339 is the highest frequency.

∴fmax=(339)(58.93)Hz=19977Hz.

<h3>What is frequency?</h3>

In physics, frequency is the number of waves that pass a given point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. After moving through a sequence of situations or locations and then returning to its initial position, a body in periodic motion is said to have experienced one cycle or one vibration. See also simple harmonic motion and angular velocity.

learn more about frequency refer:

brainly.com/question/254161

#SPJ4

7 0
2 years ago
A 90 kg person stands at the edge of a stationary children's merry-go-round at a distance of 5.0 m from its center. The person s
Paraphin [41]

Answer:

\omega = 0.016\,\frac{rad}{s}

Explanation:

The rotation rate of the man is:

\omega = \frac{v}{R}

\omega = \frac{0.80\,\frac{m}{s} }{5\,m}

\omega = 0.16\,\frac{rad}{s}

The resultant rotation rate of the system is computed from the Principle of Angular Momentum Conservation:

(90\,kg)\cdot (5\,m)^{2}\cdot (0.16\,\frac{rad}{s} ) = [(90\,kg)\cdot (5\,m)^{2}+20000\,kg\cdot m^{2}]\cdot \omega

The final angular speed is:

\omega = 0.016\,\frac{rad}{s}

3 0
3 years ago
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