Answer:
3 m/s
Explanation:
We'll begin by calculating the change in displacement of the jogger. This can be obtained as follow:
Initial displacement (d₁) = 4 m
Final displacement (d₂) = 16 m
Change in displacement (Δd) =?
Δd = d₂ – d₁
Δd = 16 – 4
Δd = 12 m
Finally, we shall determine the determine the average velocity. This can be obtained as follow:
Change in displacement (Δd) = 12 m
Time (t) = 4 s
Velocity (v) =?
v = Δd / t
v = 12 / 4
v = 3 m/s
Thus, the average velocity of the jogger is 3 m/s
Answer: Two 10-cm-diameter charged rings face each other, 25.0cm apart. Both rings are charged to +20.0nC.
Explanation:
Formulas you need for this problem:
F= mass•acceleration
KE= mass•velocity^/2
Acceleration= final velocity-intial velocity/time
time= distance/speed
t= 97.5\10= 9.75 seconds
Acc= 10-20/9.75= -1.03 m/s/s
These are the answers :)
F=650•-1.03= -669.5N
KE= 650•100/2= 32,500J or 32.5KJ
None of the above, nothing is there
Answer:
h = 17.83[m]
Explanation:
By means of the working equation which is equal to the product of force by distance, we can find the energy printed at the launch.

where:
W = work [J]
F = force = 3500 [N]
d = distance = 0.5 [m]
Now replacing:
![W= 3500*0.5\\W=1750[J]](https://tex.z-dn.net/?f=W%3D%203500%2A0.5%5C%5CW%3D1750%5BJ%5D)
Now, this same work is converted to kinetic energy, necessary for the body to move with an initial velocity. And by energy conservation, we can say that kinetic energy is transformed into potential energy. That is, the kinetic energy will be equal to the potential energy.

where:
Ekin = kinetic energy [J]
Epot = potential energy [J]
Therefore:
![1750 = m*g*h\\1750=10*9.81*h\\h = 17.83[m]](https://tex.z-dn.net/?f=1750%20%3D%20m%2Ag%2Ah%5C%5C1750%3D10%2A9.81%2Ah%5C%5Ch%20%3D%2017.83%5Bm%5D)