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timama [110]
2 years ago
14

How does the electric energy between two negativly charged particles change if one particles charge is increased by a factor of

2
Physics
1 answer:
Alinara [238K]2 years ago
8 0

Answer:

i dont know this one

Explanation:

sorry i wish i could help but if u look closley on that qyestion you will understand it mor

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A jogger moves from a position x =
vlada-n [284]

Answer:

3 m/s

Explanation:

We'll begin by calculating the change in displacement of the jogger. This can be obtained as follow:

Initial displacement (d₁) = 4 m

Final displacement (d₂) = 16 m

Change in displacement (Δd) =?

Δd = d₂ – d₁

Δd = 16 – 4

Δd = 12 m

Finally, we shall determine the determine the average velocity. This can be obtained as follow:

Change in displacement (Δd) = 12 m

Time (t) = 4 s

Velocity (v) =?

v = Δd / t

v = 12 / 4

v = 3 m/s

Thus, the average velocity of the jogger is 3 m/s

5 0
3 years ago
Two 10-cm-diameter charged rings face each other, 23.0 cm apart. Both rings are charged to 40.0 nC . What is the electric field
Volgvan

Answer: Two 10-cm-diameter charged rings face each other, 25.0cm apart. Both rings are charged to +20.0nC.

Explanation:

4 0
3 years ago
A car of mass 650 kg slows from a speed of 20.0 m/s to a speed of 10.0 m/s. How much kinetic energy has it lost. How much force
Natalija [7]
Formulas you need for this problem:
F= mass•acceleration
KE= mass•velocity^/2
Acceleration= final velocity-intial velocity/time
time= distance/speed

t= 97.5\10= 9.75 seconds
Acc= 10-20/9.75= -1.03 m/s/s

These are the answers :)
F=650•-1.03= -669.5N
KE= 650•100/2= 32,500J or 32.5KJ
7 0
4 years ago
Witch of the following is not considered to be a greenhouse gas
nevsk [136]
None of the above, nothing is there
7 0
3 years ago
Read 2 more answers
A person throws a 10kg rock straight up. If the person exerted 3500N of force on the rock over a distance
pickupchik [31]

Answer:

h = 17.83[m]

Explanation:

By means of the working equation which is equal to the product of force by distance, we can find the energy printed at the launch.

W=F*d

where:

W = work [J]

F = force = 3500 [N]

d = distance = 0.5 [m]

Now replacing:

W= 3500*0.5\\W=1750[J]

Now, this same work is converted to kinetic energy, necessary for the body to move with an initial velocity. And by energy conservation, we can say that kinetic energy is transformed into potential energy. That is, the kinetic energy will be equal to the potential energy.

W=E_{kin}=E_{pot}

where:

Ekin = kinetic energy [J]

Epot = potential energy [J]

Therefore:

1750 = m*g*h\\1750=10*9.81*h\\h = 17.83[m]

4 0
3 years ago
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