Answer: A volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.
Explanation:
Given: 
= 237 K, 
= 101.33 kPa, 
= ?
= 300 K, 
= 151.99 kPa, 
= 0.50 L
Formula used is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that a volume of 0.592 L of methane gas is required at 237 K and 101.33 kPa when the volume is decreased to 0.50 L, with a temperature of 300 K and a pressure of 151.99 kPa.
Answer:
Yes, this is true. The reason is that the flower transpires and sucks the water in and distributes it as much as it can. You can also flip it upside down and hang it with petals down , allowing the liquid to enter the flower and then retaining color for longer periods of time and having more color.
Explanation:
Based on the equation of the reaction, nitrogen is the limiting reagent while hydrogen is the excess reagent.
<h3>What is the mole ratio of hydrogen to nitrogen in the formation of ammonia?</h3>
Hydrogen and nitrogen combines to form ammonia ina mole ratio of 3 : 1 as shown by the equation of the reaction below:
The number of moles of the reactants in 14g of Nitrogen gas and 8.0g of hydrogen is calculated as follows:
Molar mass of N_{2} = 14.0 g
Molar mass of H_{2} = 2.0 g
Moles of N_{2} = 14/14.0 = 1 mole
Moles of H_{2} = 8/2.0 = 4 moles
Based on the data above:
- The limiting reagent is nitrogen gas as it will be used up while hydrogen will be left over.
- The moles of nitrogen is 1 mole
- Hydrogen is the excess reagent and 1 mole will be left over
- 3 moles of hydrogen will react with 1 mole of the nitrogen gas
- mass of 3 moles of hydrogen is 3 × 2.0 g = 6.0g
Therefore, the limiting reagent is nitrogen while hydrogen is the excess reagent.
Learn more about limiting reagent at: brainly.com/question/24945784
Answer:
A) Atom
Explanation:
An atom includes letters B, C, and D, so it must be the biggest.
