Answer : The correct expression for equilibrium constant will be:
![K_c=\frac{[C]^8}{[A]^4[B]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC%5D%5E8%7D%7B%5BA%5D%5E4%5BB%5D%5E2%7D)
Explanation :
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.
As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.
The given equilibrium reaction is,

The expression of
will be,
![K_c=\frac{[C]^8}{[A]^4[B]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC%5D%5E8%7D%7B%5BA%5D%5E4%5BB%5D%5E2%7D)
Therefore, the correct expression for equilibrium constant will be, ![K_c=\frac{[C]^8}{[A]^4[B]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BC%5D%5E8%7D%7B%5BA%5D%5E4%5BB%5D%5E2%7D)
The equilibrium constant k is actually the ratio of the
concentration of the products over the concentration of reactants at equilibrium. So if the
concentration of products < concentration of reactants, therefore the
constant k will be small. But if the concentration of products >
concentration of reactants, the constant k will be large. In this case the
value is too small (x10^-19), therefore we can say that the reaction favors the
reactant side:
the equilibrium lies far to the left
<u>Answer:</u> The equilibrium concentration of CO is 0.243 atm
<u>Explanation:</u>
We are given:
Initial partial pressure of carbon dioxide = 0.902 atm
As, carbon dioxide is present initially. This means that the reaction is proceeding backwards.
For the given chemical equation:

<u>Initial:</u> 0.902
<u>At eqllm:</u> 3x (0.902-3x)
The expression of
for above equation follows:

We are given:

Putting values in above equation, we get:

So, equilibrium concentration of CO = 3x = (3 × 0.0810) = 0.243atm[/tex]
Hence, the equilibrium concentration of CO is 0.243 atm
Answer:
1 mole is equal to 1 moles Arsenic Trichloride, or 181.2806 grams.
Explanation: