Simplify your answer and write it as a proper fra as a whole or mixed number. -7+ – 2 = ?

Mathematics

2 answers:

seropon [69]3 years ago

5 0

Whole: -9
Fraction: -9/1

ZanzabumX [31]3 years ago

4 0

the answer is -9

hope it helps

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The functions f(x)=−3/4x+2 1/4 and g(x)=(1/2)^x+1 are shown in the graph.

Svet_ta [14]

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(Using log rules)

㏑|-3x/4| - ㏑|2^-x| = ㏑|-5/4|
㏑|3x/4| - x㏑|2| = ㏑|5/4|
e^㏑|3x/4| - e^㏑|2|x = e^㏑|5/4|
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3 years ago

determine the quadratic function of f whose graph is given. The vertex is (1,-3) and the y-intercept is -2

LuckyWell [14K]

Hmmm the y-intercept is at -2? what does that mean? well, is where the graph "intercepts" or touches the y-axis, and when that happens, x = 0, so the point is really ( 0 , -2 ).

and we know where the vertex is at. Let's assume a vertical parabola, in which case the squared variable is the "x".

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex
\begin{cases}
h=1\\
k=-3
\end{cases}\implies y=a(x-1)^2-3
\\\\\\
\textit{now, we also know that }
\begin{cases}
x=0\\
y=-2
\end{cases}\implies -2=a(0-1)^2-3
\\\\\\
1=a(-1)^2\implies \boxed{1=a}\qquad thus\implies 
\begin{cases}
y=1(x-1)^2-3\\
\textit{or just}\\
y=(x-1)^2-3
\end{cases}$

6 0

3 years ago

(2a^2b + 3ab^2 - b^3) - (4b^3 - 3ab^2 -6a^2b)

skelet666 [1.2K]

Hi there!

~

$(2a^2b+3ab^2-b^3)-(4b^3-3ab^2-6a^2b)$

Distribute the Negative Sign:

$= 2a^2 b + 3ab^2 - b^3 + -1(4b^3 - 3ab^2 - 6a^2b)\\= 2a^2 b + 3ab^2 + - b^3 + -1 (4b^3) + -1 (-3ab^2) + -1 (-6a^2b)\\= 2a^2 b + 3ab^2 + -b^3 + -4b^3 + 3ab^2 + 6a^2 b$