All categories

2 years ago

Find the volume of the cone

Mathematics

1 answer:

NeTakaya2 years ago

8 0

The volume of the cone is $\frac{1}{3} \pi r^{2}h$

r: radius --> 6ft
h: height --> 6ft
$\pi$ = 3.14

Volume = $\frac{1}{3} \pi (6)^{2} *6=226.08ft^{3}$

Hope that helps!

You might be interested in

What is the initial value of the equation shown?

hodyreva [135]

C. −6, is the best option

7 0

3 years ago

Read 2 more answers

Equation for the given function

Lera25 [3.4K]

Answer:

Step-by-step explanation:

hello :

g(x) = (x+2)(x-4)/(x+2)(x-1)

1 ) this function no exist for if : x= -2 and 1

so the denominater is : (x+2)(x-1)

so : b= 2 and c=1

2) the x- intercept is : 4

so the numerater is : (x+2)(x-4)

g(x) =0 if : (x+2)(x-4)=0

means x-4=0 ... ( x+2 ≠ 0)

note :

g(x) ≠ (x-4)/(x-1) except in the case x ≠ -2

7 0

3 years ago

What matrix results from −8·A?

djverab [1.8K]

Is that all the question says can you give it into more details

So I can help you out

3 0

3 years ago

A pitcher holds 3/4 gallons of kool-aid. Martin wants to pour equal amounts of kool- aid into 6 smaller cotainers. How much kool

statuscvo [17]

Answer:

$\dfrac{1}{8}\ gallons$

Step-by-step explanation:

Amount of kool - aid that the pitcher can hold = $\frac{3}4$ gallons

There are 6 smaller containers in which this kool - aid is to be adjusted.

Also, the volume of the smaller containers is equal to each other i.e. the containers are identical to each other in terms of volume.

To find:

The amount of kool - aid that each container can hold?

Solution:

Volume of all the smaller containers combined = Volume of the kool - aid available

Let the volume of one smaller container = $V$

$V + V + V + V + V + V = \dfrac{3}{4}\ gallons$

$\Rightarrow 6V = \dfrac{3}{4}\ gallons\\\Rightarrow V = \dfrac{3}{4\times 6 }\ gallons\\\Rightarrow V=\bold{\dfrac{1}{8}\ gallons}$

$\frac{1}{8}\ gallons$ of kool - aid is the amount that each smaller can hold.

8 0

3 years ago

Is the lcm less than both numbers allways never or some times

JulijaS [17]

The lcm has to be equal to or greater than the greater of the two numbers.

7 0

3 years ago