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arsen [322]
3 years ago
11

How much money was raised with the 100 tickets solved?

Mathematics
1 answer:
V125BC [204]3 years ago
5 0

Answer:

£1481

Step-by-step explanation:

First find the cumulative frequency of the child tickets. You should get 58.

Then multiply this by the price of the child tickets.

58x12.50=£725

Then, to work out the number of adults, we subtract 58 from 100

100-58=42

Then multiply this by the price of adult tickets.

42x18=£756

Add both prices together to get your answer.

725+756=£1481

Sorry if it's too late, I hope it helps. :)

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A 12 ounce bottle of shampoo lasts Juan 16 weeks. Assuming he uses the same amount each week, write an equation relating the oun
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He uses one and one third ounces of shampoo per week.
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Let D = {x| x is a student} be the domain, and let ƒ(x) = “date of birth” be the possible function. Determine if the relation is
shusha [124]
A relation is a function if the value in its Domain does not occur more than once. This means each domain value is paired with exactly one value of range.

In the given scenario, the domain is the students (e.g name of a student) and the function returns the date of birth of the student. A student can have only one date of birth. So it is not possible that a value in Domain(i.e. a student) is paired with more than one date of births. 

Therefore, we can conclude that the given relation describes a function. 
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3 years ago
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The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding
Andru [333]

Answer:

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Step-by-step explanation:

Values (x) ∑(Xi-X)^2

----------------------------------

29.1                    0.1702

28.5                  1.0252

28.8                  0.5077

29.4                   0.0127

29.8                  0.0827

29.8                  0.0827

30.1                   0.3452

30.6                   1.1827

----------------------------------------

236.1                 3.4088

Mean = 236.1 / 8 = 29.51

S_{x}=\sqrt{3.4088/(8-1)}=0.6978

Statement of the null hypothesis:

H0: u ≥ 30 the mean wedding cost is not less than $30,000

H1: u < 30 the mean wedding cost is less than $30,000

Test Statistic:

t=\frac{X-u}{S/\sqrt{n}}=\frac{29.51-30}{0.6978/\sqrt{8}}= \frac{-0.49}{0.2467}=-1.9861

Test criteria:

SIgnificance level = 0.05

Degrees of freedom = df = n - 1 = 8 - 1 = 7

Reject null hypothesis (H0) if

t

Finding in the t distribution table α=0.05 with df=7, we have

t_{0.05,7}=2.365

t>-t_{0.05,7} = -1.9861 > -2.365

Result: Fail to reject null hypothesis

Conclusion: Do no reject the null hypothesis

u ≥ 30 the mean wedding cost is not less than $30,000

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Hope this helps!

5 0
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Answer:

1963.5

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