Answer:
should be 66.4
Step-by-step explanation:
<u>triangular prism:</u>
Using the formulas
AB=s(s﹣a)(s﹣b)(s﹣c)
V=ABh
s=a+b+c
2
Solving forV
V=1
4h﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=1
4·3·﹣24+2·(2·2)2+2·(2·2)2﹣24+2·(2·2)2﹣24≈5.19615
5.2 · 2 = 10.4
<u>Rectangular prism:</u>
<u>V=whl=2·2·14=56</u>
<u />
<u>10.4+56=66.4</u>
Answer:
The value of n is 5
Step-by-step explanation:
Here, we want to get the value of n
To get this, we will need to use the appropriate trigonometric identity
As we can see, n represents the opposite as it the side that faces the angle given
m is the hypotenuse as it is the side that faces the right angle
The last side is called the adjacent
The trigonometric identity we want to use is that which connects the opposite to the adjacent
The appropriate trigonometric identity to use in this case is the tan
Thus;
Mathematically, the tan is the ratio of the opposite to the adjacent
hence;
tan 30 = n/ 5 √3
n = 5 √3 * 1/ √3
n = 5
Answer:
Step-by-step explanation:
You are being asked to compare the value of a growing infinite geometric series to a fixed constant. Such a series will always eventually have a sum that exceeds any given fixed constant.
__
<h3>a)</h3>
Angelina will get more money from the Choice 1 method of payment. The sequence of payments is a (growing) geometric sequence, so the payments and their sum will eventually exceed the alternative.
__
<h3>c)</h3>
For a first term of 1 and a common ratio of 2, the sum of n terms of the geometric series is given by ...
Sn = a1×(r^n -1)/(r -1) . . . . . . . . . . series with first term a1, common ratio r
We want to find n such that ...
Sn ≥ 1,000,000
1 × (2^n -1)/(2 -1) ≥ 1,000,000
2^n ≥ 1,000,001 . . . . add 1
n ≥ log(1,000,001)/log(2) . . . . . take the base-2 logarithm
n ≥ 19.93
The total Angelina receives from Choice 1 will exceed $1,000,000 after 20 days.
Answer:
100000(1.04)^t=2[110000(1.04)^t
Step-by-step explanation:
B=2A
100000(1.04)^t=2[110000(1.04)^t
Answer:
The diagonal of the base is 4√5 centimeters.
The area of a base is 40 square centimeters.
The area of a lateral side between the bases is about 126.5 square centimeters.
Step-by-step explanation:
