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4 years ago

10

Is the given number a solution of the equation? Which value of c is a solution to the equation c = 2c – 4?

1 answer:

serg [7]4 years ago

5 0

C - 2c = 2c - 2c - 4
c - 2c = -4
-c = -4
c = 4

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Tanisha and Bess are sisters. Tanisha is half as old as Bess. Bess is 6 years older than Tanisha.

aleksklad [387]

Answer:

D

Step-by-step explanation:6+6=12

12/2=6

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3 years ago

B is opposite __________.

sukhopar [10]

Answer: OPTION D.

Step-by-step explanation:

By definition, the opposite side of a triangle is that side that is on the opposite direction of an angle.

As you can see, the triangle ABC shown in the figure attached in the problem has the angles: ∠A, ∠B and ∠C.

Then, the angle ∠A is opposite to BC, the angle ∠B is opposite to AC and the angle ∠C is opposite to AB.

Therefore, you can conclude that the answer is the option D, which is: AC.

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3 years ago

Fernando followed two diagonal paths, Paths 1 and 2, to get from his house, F, to a neighborhood corner store, C, as shown below

aleksandrvk [35]

Answer:

42 meters

Step-by-step explanation:

Given

See attachment for complete question

Required

Calculate distance FC

FC is calculated as:

$FC = Path\ 1 + Path\ 2$

Where

$Path\ 1 = FB$

$Path\ 2 = BC$

Considering $\triangle FEB$ , we have:

$FB^2 = FE^2 + BE^2$ --- Pythagoras theorem

Where

$FE = FD - BA$

$FE = 22m - 15m$

$FE = 7m$

and

$BE = CD - CA$

$BE = 32m - 8m$

$BE = 24m$

So:

$FB^2 = FE^2 + BE^2$

$FB^2 = 7^2 +24^2$

$FB^2 = 49 +576$

$FB^2 = 625$

Take square roots of both sides

$FB = 25$

So:

$Path\ 1 = 25$

Considering $\triangle BAC$ , we have:

$BC^2 = BA^2 + AC^2$ --- Pythagoras theorem

Where:

$BA = 15$ and $AC = 8$

So, we have:

$BC^2 = 15^2 + 8^2$

$BC^2 = 225 + 64$

$BC^2 = 289$

Take square roots of both sides

$BC = 17$

So;

$Path\ 2= 17$

Recall that:

$FC = Path\ 1 + Path\ 2$

$FC = 25 + 17$

$FC = 42$

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frozen [14]

You have to make the lines congruent so it is 23by10

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zepelin [54]

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3 years ago

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