3 years ago

Is the given number a solution of the equation? Which value of c is a solution to the equation c = 2c – 4?

Mathematics

1 answer:

serg [7]3 years ago

5 0

C - 2c = 2c - 2c - 4
c - 2c = -4
-c = -4
c = 4

You might be interested in

Do you guys know this please help me?

Alik [6]

For apple flavor because they are most=18 so they will get the chance to picked easily.

Likely goes to Apple one

Equally likely goes to 8 cinnamon and maple.

Unlikely for Plain because they are least=6

Impossible for chocolate chips because they are no choco flavor he bough

4 0

3 years ago

2x + 4(x+3)= 42 I just want to give people some points also I need this answer

NARA [144]

Reduces to 6x=30
the answer is x= 5

5 0

3 years ago

Read 2 more answers

4. Given the data below, where X is the independent variable and Y is the dependent variable. If you

oksian1 [2.3K]

The answer is A, look at the difference between 0 and 15 (15) and the difference between 5 and 10 (5) then divide them 5/15.

3 0

3 years ago

Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx

uranmaximum [27]

Given the differential equation

$5t^3 \frac{dx}{dt} +2x-2=0$

The solution is as follows:

$5t^3 \frac{dx}{dt} +2x-2=0 \\ \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\ \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\ \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\ \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\ \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\ \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\ \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\ \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1$

3 0

3 years ago

Ryan has 3 times as many nickels as dimes. The coins have a total of $1.50. How many of each coin foes he have?

mafiozo [28]

0.5?maybe I just divided 1.50 by 3

5 0

3 years ago

Read 2 more answers