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zzz [600]
4 years ago
13

What are the reactants in burning waste? What products are obtained from burning waste?

Chemistry
2 answers:
MA_775_DIABLO [31]4 years ago
6 0

Answer:

ash, smoke, carbon dioxide are obtained from burning waste

SIZIF [17.4K]4 years ago
6 0

Answer:

the reactants in burning waste are :- oxygen & the waste. ( combustion requires oxygen)

products:- ash, carbon dioxide and water vapor

Explanation:

Burning waste is an example of combustion but it is however not environment  friendly as it leads to emission of large amount of carbon dioxide which pollutes the environment.

Burning of waste also produces a lot of solid residue and sometimes chemical  waste which can be difficult to treat and dispose. The careless and untreated dumping of these residues or waste will lead to soil degradation and eventually lead to soil pollution.

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The percentage of oxygen in sulphur lv oxide (s=32, o=16)​
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3 years ago
Which element in the Southwestern desert ecosystem is abiotic?
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8 0
3 years ago
Read 2 more answers
Find an expression for the change in entropy when two blocks of the same substance of equal mass, one at the temperature Th and
Gre4nikov [31]

Explanation:

Relation between entropy change and specific heat is as follows.

            \Delta S = C_{p} log (\frac{T_{2}}{T_{1}})

The given data is as follows.

     mass = 500 g,         C_{p} = 24.4 J/mol K

     T_{h} = 500 K,          T_{c} = 250 K               

   Mass number of copper = 63.54 g /mol

Number of moles = \frac{mass}{/text{\molar mass}}

                                 = \frac{500}{63.54}

                                 = 7.86 moles

Now, equating the entropy change for both the substances as follows.

     7.86 \times 24.4 \times [T_{f} - 250] = 7.86 \times 24.4 \times [500 -T_{f}]

       T_{f} - 250 = 500 - T_{f}

          2T_{f} = 750

So,       T_{f} = 375^{o}C

  • For the metal block A,  change in entropy is as follows.

         \Delta S = C_{p} log (\frac{T_{2}}{T_{1}})

              = 24.4 log [\frac{375}{500}]

              = -3.04 J/ K mol

  • For the block B,  change in entropy is as follows.

         \Delta S = C_{p} log (\frac{T_{2}}{T_{1}})

                  = 24.4 log [\frac{375}{250}]

                  = 4.296  J/Kmol

And, total entropy change will be as follows.

                       = 4.296 + (-3.04)

                      = 1.256 J/Kmol

Thus, we can conclude that change in entropy of block A is -3.04 J/ K mol  and change in entropy of block B is 4.296  J/Kmol.

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3 years ago
If a large chunk of sulfur is ground into powder, its mass will ___
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Its mass will stay the same
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Summarize how methylmercury can biomagnify in the food chain. <br><br>​
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it can change the ways others eat

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