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julsineya [31]
3 years ago
8

Summarize how methylmercury can biomagnify in the food chain. ​

Chemistry
1 answer:
dmitriy555 [2]3 years ago
4 0

Answer:

it can change the ways others eat

Explanation:

because the methylmercury depends on the animal

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The complete balanced equation for the reaction between barium hydroxide and acetic<br> acid is
TiliK225 [7]

Answer:

2 CH3COOH + Ba(OH)2 --> Ba(C2H3O2)2 + 2H2O

To make it less clustered, you can use Ac for C2H3O2.

2 HAc + Ba(OH)2 --> Ba(Ac)2 + 2H2O

The acetic acid reacts with the base barium hydroxide to form the salt barium acetate and water.

Explanation:

final answer. C

3 0
3 years ago
Plaseee ASAP
Umnica [9.8K]

Answer:

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7 0
3 years ago
Why do scientists look for patterns in the world​
Margarita [4]

Answer:

to do day-to day activities easily and make surrounding comfortable for man

Explanation:

as an example , binary numbers help to work computers ,calculators.they help us lot .

scientific methods also need to write large and small numbers in short ways .so, scientists find various patterns .

6 0
3 years ago
Be sure to answer all parts. an aqueous solution of a strong base has a ph of 10. 220 at 25°c. calculate the concentration of th
tia_tia [17]

An aqueous solution of a strong base has a pH of 10. 220 at 25°C then concentration of the base if the base is

(a)  LiOH =  1.66×10^{-4}  M

(b)  Ba(OH)_{2 =  3.32×10^{-4}M

Calculation ,

For calculation of concentration of the   LiOH and  Ba(OH)_{2 first we have to calculate pOH of the solution.

pH + pOH = 14

pOH = 14 - pOH = 14 - 10.22  = 3.78

pOH = -㏒ [ OH^{-} ]

[ OH^{-} ] = 10^{-pH} =  10^{-3.78} = 1.66×10^{-4}

So ,  concentration of the base LiOH =  1.66×10^{-4}

So ,  concentration of the base Ba(OH)_{2 =  1.66×10^{-4} ×2 = 3.32×10^{-4}

To learn more about strong base please click here

brainly.com/question/16749233

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6 0
2 years ago
Calculate the approximate enthalpy of the reaction in joules. Estimate that 1.0 mL of vinegar has the same thermal mass as 1.0 m
Nesterboy [21]

Explanation:

The given data is as follows.

   Density of vinegar = 1.0 g/ml

   Specific heat capacity = 4.25 J/g ^{o}C

   T_{1} = 17 ^{o}C,  and   T_{2} = 14 ^{o}C

Relation between enthalpy and specific heat is as follows.

                   \Delta H = mC \Delta T

Hence, putting the values into the above formula as follows.

          \Delta H = mC \Delta T

                  = 25 \times 1.0 \times 4.25 J/g ^{o}C \times -3^{o}C          (as density = \frac{mass}{volume})

                               = - 315 J

Thus, we can conclude that the enthalpy of reaction is -315 J.

As the value is negative so, it means that heat is releasing. Hence, the reaction is exothermic in nature.

5 0
3 years ago
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