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KIM [24]
2 years ago
7

A helium balloon possesses a volume of 2500 L at a temperature of 114 °C. What volume will the balloon have if the temperature c

hanges to 56 °C? The pressure remains constant
Chemistry
1 answer:
Ivenika [448]2 years ago
3 0

Given that the pressure remains constant, if the temperature of the helium balloon decreases to the given value, the volume increases to 2125.5L.

<h3>What is Charles's law?</h3>

Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.

It is expressed as;

V₁/T₁ = V₂/T₂

Given the data in the question;

  • Initial temperature of gas T₁ = 114°C = (114+273.15)K = 387.15K
  • Initial volume of gas V₁ = 2500L
  • Final temperature T₂ = 56°C = (56+273.15)K = 329.15K
  • Final volume V₂ = ?

V₁/T₁ = V₂/T₂

V₂ = V₁T₂ / T₁

V₂ = ( 2500L × 329.15K ) / 387.15K

V₂ = 882875LK / 387.15K

V₂ = 2125.5L

Given that the pressure remains constant, if the temperature of the helium balloon decreases to the given value, the volume increases to 2125.5L.

Learn more about Charles's law here: brainly.com/question/12835309

#SPJ1

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1. If a solution of sodium chloride has 22.3 g of
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<u>We are given:</u>

Mass of NaCl in the given solution = 22.3 grams

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<u>Number of Moles of NaCl:</u>

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Number of moles = 22.3 / 58.44 = 0.382 moles

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7 0
3 years ago
What’s the answer ?
Romashka-Z-Leto [24]

Answer:

45.3°C

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 82KPa

Initial temperature (T1) = 26°C

Final pressure (P2) = 87.3KPa.

Final temperature (T2) =.?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K.

Step 3:

Determination of the new temperature of the gas. This can be obtained as follow:

P1/T1 = P2/T2

82/299 = 87.3/T2

Cross multiply to express in linear form

82 x T2 = 299 x 87.3

Divide both side by 82

T2 = (299 x 87.3) /82

T2 = 318.3K

Step 4:

Conversion of 318.3K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T(K) = 318.3K

T(°C) = 318.3 – 273

T(°C) = 45.3°C.

Therefore, the new temperature of the gas in th tire is 45.3°C

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3 years ago
Ionization energy definition?
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Answer:

In physics and chemistry, ionization energy or ionisation energy, is the minimum amount of energy required to remove the most loosely bound electron of an isolated neutral gaseous atom or molecule.

I hoped this helped :D

Explanation:

5 0
3 years ago
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