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KIM [24]
2 years ago
7

A helium balloon possesses a volume of 2500 L at a temperature of 114 °C. What volume will the balloon have if the temperature c

hanges to 56 °C? The pressure remains constant
Chemistry
1 answer:
Ivenika [448]2 years ago
3 0

Given that the pressure remains constant, if the temperature of the helium balloon decreases to the given value, the volume increases to 2125.5L.

<h3>What is Charles's law?</h3>

Charles's law states that "the volume occupied by a definite quantity of gas is directly proportional to its absolute temperature.

It is expressed as;

V₁/T₁ = V₂/T₂

Given the data in the question;

  • Initial temperature of gas T₁ = 114°C = (114+273.15)K = 387.15K
  • Initial volume of gas V₁ = 2500L
  • Final temperature T₂ = 56°C = (56+273.15)K = 329.15K
  • Final volume V₂ = ?

V₁/T₁ = V₂/T₂

V₂ = V₁T₂ / T₁

V₂ = ( 2500L × 329.15K ) / 387.15K

V₂ = 882875LK / 387.15K

V₂ = 2125.5L

Given that the pressure remains constant, if the temperature of the helium balloon decreases to the given value, the volume increases to 2125.5L.

Learn more about Charles's law here: brainly.com/question/12835309

#SPJ1

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