The amount of diffraction of sound waves depends on the medium the sound wave travels to and the frequency. Diffraction happens as soon as it has been out of the source.
1/2mv^2
1/2x12x10^2=600J
The kinetic energy is 600J
That's a <em>parallel</em> circuit. <em>(B)</em>
When current from Point-A reaches the 3-way intersection just to the right of Point-B, it has to make a choice: Either turn left, go through B, and light the lower bulb, or go straight and light the upper bulb.
A circuit that has any "decision" points in it is a parallel circuit. What happens in the real world is: The current splits up. Some of the current that reaches the intersection turns left toward Point-B, and the rest of it goes straight up.
A series circuit is one in which there's only one possible path all the way around. There are no intersections of more than 2 roads, and no electron ever has to decide which way to flow.
An open circuit is one in which there's a break somewhere along the line and electrons can't jump across it. It's like a railroad where a big piece is cut out of the track somewhere. So no trains can travel on that route, and there's no current flowing anywhere in the circuit.
I'm not so sure about a "combination" circuit. I guess you could give that name to a complicated circuit that has some series parts and some parallel-parts. Personally, I'd call that a "series-parallel" circuit. But it really doesn't matter right now. Whatever the word means, the circuit in the picture is definitely not a "combination" circuit.
Answer:
The direction the plane would have to fly to compensate for a wind velocity of 62.0 km/h[N] is 4.5° S of W
Explanation:
The given parameters are;
Velocity of Jet = 792 km/h
Direction of jet velocity = West
Velocity of wind = 62.0 km/h
Direction of wind velocity = North
Therefore, the jet has to have a component of 62.0 km/h South of West to compensate for the wind velocity
The direction of the plane, θ° South of West (S of W) to compensate for the wind is given as follows;
Therefore;
The direction the plane would have to fly to compensate for a wind velocity of 62.0 km/h[N] = 4.5° S of W.
Answer:
Explanation:
given,
weight of the man = 680 N
weight of the woman = 500 N
mass of man = 
M_m = 69.4 Kg
mass of woman
= 
M_w = 51 Kg
ratio of man's kinetic energy Km to that of the woman Kw
momentum is same
