Solo estoy aquí por la libra, lo siento, no pude ayudar
Answer:
Part A: Q = 0.075C
Part B: E = 187.5J
Part C: I = 50A
Part D: ΔQ 1.53C
Explanation:
Part A
Q = C×V
Given
C = 15μF = 15×10‐⁶ F, V = 5kV = 5000V
Q = 15×10‐⁶× 5000 = 0.075C
Part B
Energy = E = 1/2 ×CV² = 1/2 × 15×10‐⁶ × 5000² = 187.5J
Part C
Given R = 100Ω
V = IR, I = V/R = 5000/100 = 50A
Part D
I = ΔQ/Δt
Given Δt= 90ms = 90×10-³s, I = 17A
ΔQ = I × Δt = 17×90×10-³ = 1.53 C
B) A ladybug crawling forward at constant rate of 2.5 m/s
The answer is 300 feet. The stop lamp or lamps on the rear of a vehicle must show a red light that is set in motion upon application of the service or foot brake and, in a vehicle manufactured or assembled on or after January 1, 1964, must be visible from a distance of not less than 300 feet to the rear in normal sunlight. Take note, if the vehicle is manufactured or assembled January 1, 1964, the stop lamp or lamps must be visible from a distance of not less than 100 feet. Also, the stop lamp may be combined with one or more other rear lamps.
