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Nesterboy [21]
3 years ago
7

A cube and a square pyramid were joined to form the composite solid. A cube with side lengths of 12 inches. A square pyramid wit

h triangular sides with a height of 9 inches. What is the total surface area of the composite solid? 792 square inches 936 square inches 1,080 square inches 1,152 square inches Mark this and return
Physics
2 answers:
oee [108]3 years ago
7 0

Answer:

The answer is 936 inches squared on Edg 2020 <33

Explanation:

Vesna [10]3 years ago
6 0

Answer:

i think it is the first option.

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Which is a chemical property of ford ?<br><br> malleability <br> conductivity <br> flammability
Makovka662 [10]
Malleability because it is
7 0
3 years ago
What hero means to me is when a person will do good things for others, no matter how bad it is for them. Also to me a hero is so
posledela

Answer:

good job my boy this is the right answer

Explanation:

8 0
2 years ago
Read 2 more answers
8) Find the X and Y component of 10degree vector that has 5N.
Deffense [45]

Answer:

Fx  = 4.92 [N]

Fy = 0.868 [N]

Explanation:

Let's take the 10 degrees as a measure from the horizontal component to the vector.

Thus taking the components in the X & y axes respectively:

Fx = 5*cos(10) = 4.92 [N]

Fy = 5*sin(10) = 0.868 [N]

3 0
3 years ago
The uncertainty in the position of an electron along an x axis is given as 53 pm, which is about equal to the radius of a hydrog
Jobisdone [24]

To solve this problem it is necessary to apply the concepts related to the Heisenberg's uncertainty principle. Under this principle we understand the relationship that the minimum range of error in position (x) times the minimum range of error in momentum (p) is, at a minimum, about equal to the Planck constant, mathematically that is,

\Delta p = \frac{h}{\Delta x}

Replacing with our values we have,

\Delta p = \frac{6.63*10^{-34}J\cdot s}{2\pi (53*10^{-12}m)}

\Delta p = 1.99*10^{-24} kg\cdot m/s

Therefore the least uncertainty in any simultaneous measurement of the momentum component px of this electron is 1.99*10^{-24} kg\cdot m/s

4 0
3 years ago
A steel bridge is 1000 m long at -20°C in winter. What is the change in length when the temperature rises to 40°C in summer? The
xenn [34]

Answer:

ΔL = 0.66 m

Explanation:

The change in length on an object due to rise in temperature is given by the following equation of linear thermal expansion:

ΔL = αLΔT

where,

ΔL = Change in Length of the bridge = ?

α = Coefficient of linear thermal expansion = 11 x 10⁻⁶ °C⁻¹

L = Original Length of the Bridge = 1000 m

ΔT = Change in Temperature =  Final Temperature - Initial Temperature

ΔT = 40°C - (-20°C) = 60°C

Therefore,

ΔL = (11 x 10⁻⁶ °C⁻¹)(1000 m)(60°C)

<u>ΔL = 0.66 m</u>

6 0
4 years ago
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