A. A control group is given the experimental treatment.
Answer:
a) v₀ = 39.83 v / s
, b) y = 111.94 m
Explanation:
a) Let's use the kinematic relations for this problem
v² = v₀² - 2 g y
The speed at the base of the cliff is 30 m / s, the height y = 31 m
v₀² = v² + 2 g y
v₀ =√ (30² + 2 9.8 31)
v₀ = 39.83 v / s
b) at the point of maximum height the speed is zero
0 = v₀² - 2 g (y –y0)
y = y₀ + v₀² / 2g
.y = 31 + 39.83²/2 9.8
y = 111.94 m
Choice-D is a simple statement of Newton's 2nd law of motion.
Answer:
It takes <u>2.93 s</u> for the object to reach ground from the height of 42 m.
Explanation:
Given:
Displacement of the object is,
As it is dropped, initial velocity of the object is,
Acceleration of the object is equal to acceleration due to gravity and is equal to,
Now, using Newton's equation of motion and plugging in the values, we get:
So, it takes 2.93 s for the object to reach ground from the height of 42 m.
Uneven heating of land and sea causes warm air over land to rise up, creating a low pressure zone. So wind blows in from the sea to fill this low pressure zone